Exercise 6: [Challenge] Suppose that you have a covering of a sphere by finitely many (closed) hemispheres. Prove that there is a subcollection of less than five hemispheres that cover the sphere. Remark: A set is called closed if it contains its boundary points. In the case of a hemisphere, this means it contains the boundary (great) circle. Compare to a closed interval, e.g., the interval 0, 1] is closed since it contains the boundary points of 0 and 1. Last modified: October 2, 2019, Due: October 9, 2019. 1 Hint 1: Consider the case of five hemispheres. Prove that four hemispheres suffice. Hint 2: Consider the case of a circle: Show that if four semicircles cover a circle, then three of them suffice.
Exercise 6: [Challenge] Suppose that you have a covering of a sphere by finitely many (closed) hemispheres. Prove that there is a subcollection of less than five hemispheres that cover the sphere. Remark: A set is called closed if it contains its boundary points. In the case of a hemisphere, this means it contains the boundary (great) circle. Compare to a closed interval, e.g., the interval 0, 1] is closed since it contains the boundary points of 0 and 1. Last modified: October 2, 2019, Due: October 9, 2019. 1 Hint 1: Consider the case of five hemispheres. Prove that four hemispheres suffice. Hint 2: Consider the case of a circle: Show that if four semicircles cover a circle, then three of them suffice.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Suppose that you have a covering of a sphere by finitely many( closed) hemispheres. Prove that there is a sub collection of less than five hemispheres that cover the sphere.
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