EXERCISE 3.6 Winter lasts from December 21 through March 21. The average win-ter temperature in Boston is Normally distributed with mean μ = 32.5° F and stan-dard deviation o = 1.59° F. In New York City, the average winter temperature isNormally distributed with mean = 35.4 ° F and standard deviation o = 2.05°F.(a) What is the probability that the average winter temperature in Boston this com-ing winter will be above freezing (32 ° F)?(b) Assume that average winter temperatures in Boston and New York are inde-pendent. What is the probability that the average temperature in Boston in thecoming winter will be higher than in New York?(c) Do you think the independence assumption above is reasonable?EXERCISE FI

The provided information is as follows:The average winter temperature in Baston is .The standard…

Answered: EXERCISE 3.6 Winter lasts from December…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The life of Sunshine CD players is normally distributed with mean of 4.2 years and a standard deviation of 1.1 years. A CD player is guaranteed for three years. We are interested in the length of time a CD player lasts. Find the 85th percentile of the distribution for the time a CD player lasts. Round your answer to two decimal places, if necessary. The 85th percentile is______.
The annual per capita consumption of oranges (in pounds) in the United States can be approximated by a normal distribution. The mean annual per capita of oranges is 19.2 with a standard deviation of 4 pounds. what annual per capita consumption of oranges represents the 5th percentile?
Accordi the historical data, the life expectancy in Mexico is equal to the life expectancy in Spain. A new study has been made to see whether this has changea. Records of 205 individuals from Mexico who died recently are selected at random. The 205 individuals lived an average of 71.8 years with a standard deviation of 2.6 years. Records of 250 individuals from Spain who died recently are selected at random and independently. The 250 individuals lived an average of 71.2 years with a standard deviation of 3.0 years. Assume that the population standard deviation of the life expectancy can be estimated by the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the life expectancy, H1, in Mexico is not equal to the life expectancy, µ,, in Spain anymore? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to at least three…
A manufacturer knows that their items lifespans are normally distributed with mean = 5.6 and standard deviation = 0.8.What proportion of the items' lifespans will be longer than 8 years?___________________ Round to 4 decimal places.
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A study discovered that Americans consumed an average of 13.2 pounds of chocolate per year. Assume that the annual chocolate consumption follows the normal distribution with a standard deviation of 3.2 pounds. d. What is the probability that an American will consume exactly 12 pounds of chocolate next year? enter your response here (Round to four decimal places as needed.) Part 5 e. What is the annual consumption of chocolate that represents the 80th percentile? The 80th percentile is represented by an annual consumption of enter your response here pounds of chocolate. (Type an integer or decimal rounded to one decimal place as needed.)
Assume that females have pulse rates that are normally distributed with a mean of μ=74.0 beats per minute and a standard deviation of σ=12.5 beats per minute. Complete parts (a) through (c) below. Question content area bottom Part 1 a. If 1 adult female is randomly selected, find the probability that her pulse rate is between 67 beats per minute and 81 beats per minute. The probability is 0.42450.4245. (Round to four decimal places as needed.) Part 2 b. If 4 adult females are randomly selected, find the probability that they have pulse rates with a mean between 67 beats per minute and 81 beats per minute. The probability is enter your response here. (Round to four decimal places as needed.)

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