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Exercise 3. The following circuit shows a balanced three-phase AC system. (A, B, C) is a direct sequence. The following measures are known: W1 = 12309.4 W; W2 = 7690.6W; and V1 = 400V. a) Find the value of the impedance ZL. b) Find the current measured by the ammeter A and voltage measured by the voltmeter V2. + + + W1 ZL = R+jXQ V1 ZL = R+jXQ W2 V2 ZL = R+jXQ A Figure 3. Three-phase AC system 3 Solution: a) ZL10.24+0.512; 2; b) A = 18.04 A; V2=689.4V 3-Phase Balanced Load P = 10 KW Power factor = 0.8 (i) Activate Go to Settings

Exercise 3. The following circuit shows a balanced three-phase AC system. (A, B, C) is a direct sequence. The following measures are known: W1 = 12309.4 W; W2 = 7690.6W; and V1 = 400V. a) Find the value of the impedance ZL. b) Find the current measured by the ammeter A and voltage measured by the voltmeter V2. + + + W1 ZL = R+jXQ V1 ZL = R+jXQ W2 V2 ZL = R+jXQ A Figure 3. Three-phase AC system 3 Solution: a) ZL10.24+0.512; 2; b) A = 18.04 A; V2=689.4V 3-Phase Balanced Load P = 10 KW Power factor = 0.8 (i) Activate Go to Settings

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Exercise 3. The following circuit shows a balanced three-phase AC system. (A, B, C) is a direct sequence. The following measures are known: W1 = 12309.4 W; W2 = 7690.6W; and V1 = 400V. a) Find the value of the impedance ZL. b) Find the current measured by the ammeter A and voltage measured by the voltmeter V2. + + + W1 ZL = R+jXQ V1 ZL = R+jXQ W2 V2 ZL = R+jXQ A Figure 3. Three-phase AC system 3 Solution: a) ZL10.24+0.512; 2; b) A = 18.04 A; V2=689.4V 3-Phase Balanced Load P = 10 KW Power factor = 0.8 (i) Activate Go to Settings
Transcribed Image Text:Exercise 3. The following circuit shows a balanced three-phase AC system. (A, B, C) is a direct sequence. The following measures are known: W1 = 12309.4 W; W2 = 7690.6W; and V1 = 400V. a) Find the value of the impedance ZL. b) Find the current measured by the ammeter A and voltage measured by the voltmeter V2. + + + W1 ZL = R+jXQ V1 ZL = R+jXQ W2 V2 ZL = R+jXQ A Figure 3. Three-phase AC system 3 Solution: a) ZL10.24+0.512; 2; b) A = 18.04 A; V2=689.4V 3-Phase Balanced Load P = 10 KW Power factor = 0.8 (i) Activate Go to Settings
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