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Exercise 3. sin(3z) Let f(z) and C: |z – n| = 1. Then S. f(z)dz = z²(z-n) а. О b. 2ni с. — 2пі d. None of the above

Exercise 3. sin(3z) Let f(z) and C: |z – n| = 1. Then S. f(z)dz = z²(z-n) а. О b. 2ni с. — 2пі d. None of the above

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.7: Operations On Functions
Problem 58E
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Exercise 3. sin(3z) Let f(z) and C: |z – 1| = 1. Then ſ. f(z)dz = z²(z-n) а. О b. 2ni с. —2пі d. None of the above
Transcribed Image Text:Exercise 3. sin(3z) Let f(z) and C: |z – 1| = 1. Then ſ. f(z)dz = z²(z-n) а. О b. 2ni с. —2пі d. None of the above
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