Exercise 3. Read the boxed definitions on p. 767. According to these definitions, how are the  concepts of velocity and speed defined here different?

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Exercise 3. Read the boxed definitions on p. 767. According to these definitions, how are the 
concepts of velocity and speed defined here different?

N
FIGURE 13.7 The curve and the
velocity vector when - 77/4 for the
motion given in Example 4.
Solution The velocity and acceleration vectors at time i are
and the speed is
v(t) = r' (t) = -2 sin ti + 2 cos tj 10 cos t sin t k
= -2 sin ti + 2 cos tj - 5 sin 2rk,
a(t) = r"(t) = -2 costi - 2 sin tj- 10 cos 21 k.
|v(t) = √(-2 sin t)² + (2 cos t)² + (−5 sin 2r)² = V4 + 25 sin² 2t.
When 1 = 77/4, we have
7T
4
√29.
A sketch of the curve of motion, and the velocity vector when t = 77/4, can be seen in
Figure 13.7.
√21 + √2j + 5k,
7T
4
= -√2i + √2j.
7 T
|(¹)|-
We can express the velocity of a moving particle as the product of its speed and
direction:
Velocity = = (speed) (direction).
|v||
Differentiation Rules
Because the derivatives of vector functions may be computed component by component,
the rules for differentiating vector functions have the same form as the rules for differenti-
ating scalar functions.
Transcribed Image Text:N FIGURE 13.7 The curve and the velocity vector when - 77/4 for the motion given in Example 4. Solution The velocity and acceleration vectors at time i are and the speed is v(t) = r' (t) = -2 sin ti + 2 cos tj 10 cos t sin t k = -2 sin ti + 2 cos tj - 5 sin 2rk, a(t) = r"(t) = -2 costi - 2 sin tj- 10 cos 21 k. |v(t) = √(-2 sin t)² + (2 cos t)² + (−5 sin 2r)² = V4 + 25 sin² 2t. When 1 = 77/4, we have 7T 4 √29. A sketch of the curve of motion, and the velocity vector when t = 77/4, can be seen in Figure 13.7. √21 + √2j + 5k, 7T 4 = -√2i + √2j. 7 T |(¹)|- We can express the velocity of a moving particle as the product of its speed and direction: Velocity = = (speed) (direction). |v|| Differentiation Rules Because the derivatives of vector functions may be computed component by component, the rules for differentiating vector functions have the same form as the rules for differenti- ating scalar functions.
Chapter 13 Vector-Valued Functions and Motion in Space
13.1 Curves in Space and Their Tangents
DEFINITIONS If r is the position vector of a particle moving along a smooth
curve in space, then
v(1)
dt
is the particle's velocity vector, tangent to the curve. At any time 1, the direction
of v is the direction of motion, the magnitude of v is the particle's speed, and
the derivative a = dv/dt, when it exists, is the particle's acceleration vector. In
summary,
1. Velocity is the derivative of position:
2. Speed is the magnitude of velocity:
3. Acceleration is the derivative of velocity:
Speed v
=
767
dvd²r
dt²
dt
4. The unit vector v/v is the direction of motion at time t.
EXAMPLE 4 Find the velocity, speed, and acceleration of a particle whose motion in
space is given by the position vector r(t) = 2 costi + 2 sin tj + 5 costk. Sketch the
velocity vector v(7#/4).
Transcribed Image Text:Chapter 13 Vector-Valued Functions and Motion in Space 13.1 Curves in Space and Their Tangents DEFINITIONS If r is the position vector of a particle moving along a smooth curve in space, then v(1) dt is the particle's velocity vector, tangent to the curve. At any time 1, the direction of v is the direction of motion, the magnitude of v is the particle's speed, and the derivative a = dv/dt, when it exists, is the particle's acceleration vector. In summary, 1. Velocity is the derivative of position: 2. Speed is the magnitude of velocity: 3. Acceleration is the derivative of velocity: Speed v = 767 dvd²r dt² dt 4. The unit vector v/v is the direction of motion at time t. EXAMPLE 4 Find the velocity, speed, and acceleration of a particle whose motion in space is given by the position vector r(t) = 2 costi + 2 sin tj + 5 costk. Sketch the velocity vector v(7#/4).
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