Exercise 2: Let f(x) = sec2(x), and g(x) = tan2(x). Prove f'(x) = g' (x). Thus, find a C E R such that sec2(r)tan2(x) C for all x € (-7/2,7/2).

Q: Let f'(x)= = f(x) = x² tan ¹(7x)

A:

Q: Let Compute f'(2). ƒ(x) = x³ + 3ª

A: This is a problem related to differentiation of the function. Please follow the procedure given…

Q: Consider the function f(x) = In (x - 4) a.) Use the First Derivative Test or the Second Derivative…

A:

Q: Find f'(x) if f(x) = tan-1 2x sec²(x) 1 1+x² 2x 1+x² 2x 1+x¹ 2x 1+x² 1-¹ (x²).

A:

Q: 2. Use the derivative rules to find f (x). (a) f(x) = (2x® – 8x-2 + 9) +) 3 (b) f(x) = COS x CSCX_…

A: Find the derivative

Q: Find f. f'(t) = sec(t)(sec(t) + tan(t)), = -1 f(t) =

A: Given that: f'(t)=sect(sect+tant),    -π2<t<π2, fπ4=-1

Q: Evaluate / tan*(x) sec*(x) dæ.

A: I=∫tan3(x)sec2(x)dxsubstitute  tanx=udiffrentiatesex2xdx=du