Exercise #2: In the following diagram of right triangle AABC , the altitude has been drawn from vertex C to the hypotenuse АВ , creating two additional right triangles, AACD and ACBD . (a) Why can you argue that AABC ~ AACD ? Likewise AABC ~ ACBD ? (b) Based on (a), why can you argue that AACD ~ ACBD ? B (c) Draw the two smaller triangles in the same orientation as AABC . (d) If AD=8 and BD=2 then find the length of CD and BC . Express all answers in simplest form.
Exercise #2: In the following diagram of right triangle AABC , the altitude has been drawn from vertex C to the hypotenuse АВ , creating two additional right triangles, AACD and ACBD . (a) Why can you argue that AABC ~ AACD ? Likewise AABC ~ ACBD ? (b) Based on (a), why can you argue that AACD ~ ACBD ? B (c) Draw the two smaller triangles in the same orientation as AABC . (d) If AD=8 and BD=2 then find the length of CD and BC . Express all answers in simplest form.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![Exercise #2: In the following diagram of right triangle AABC , the altitude has been drawn from vertex C to the
hypotenuse AB , creating two additional right triangles, AACD and ACBD .
(a) Why can you argue that AABC ~ AACD ? Likewise AABC ~ ACBD ?
A
(b) Based on (a), why can you argue that AACD ~ ACBD ?
(c) Draw the two smaller triangles in the same orientation as AABC .
(d) If AD=8 and BD=2 then find the length of CD and BC
Express all answers in simplest form.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7d6e42e-a424-4025-8d71-0c8828719de4%2F0a142117-2e7c-45d5-a737-4c4fdffd909d%2Fdcla183_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Exercise #2: In the following diagram of right triangle AABC , the altitude has been drawn from vertex C to the
hypotenuse AB , creating two additional right triangles, AACD and ACBD .
(a) Why can you argue that AABC ~ AACD ? Likewise AABC ~ ACBD ?
A
(b) Based on (a), why can you argue that AACD ~ ACBD ?
(c) Draw the two smaller triangles in the same orientation as AABC .
(d) If AD=8 and BD=2 then find the length of CD and BC
Express all answers in simplest form.
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