Exercise 2:in scilabWrite a code to plot the 2 signals: y1= sin(t); y2 = sin(2*t) and their sum on an interval t = [-10, 10]. Usea step of 0.1The 3 plots should be on the same figure on three rows (use subplot).

CODE IN SCILAB t = -10:0.1:10; y1 = sin(t);y2 = sin(2*t);y3 = y1 + y2; subplot(3,1,1);plot(t,y1);…

Answered: Exercise 2: in scilab Write a code to…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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The Problem: You are coding a graphics filter that process each of an image through a filter. Each pixel is defined a triplet of real numbers (R,G,B) each of which is between 0 and 255.The filtering algorithms need to work on real numbers in order to do their job. But examining the program you discover that they only need two digits of accuracy. Any additional digits is just overkill.
Aim Using a for loop and a range function, you have been asked to find the even numbers between 5 and 55 and then find their sum. Steps for Completion 1. Define a counter for the sum named total_sum. 2. Define a for loop with an even range for numbers between 5 and 55. 3. Add each looped number to the sum. 4. Outside the loop, print out total_sum. The output should be as shown in Snippet 3.50: 750 Snippet 3.50
this in r language The following code is a simulation of the central limit theorem. In the code we generate 36 observations from a random exponential distribution with mean 1 and variance 1. We then use a for loop to generate averages of these 36 observations to display in a histogram. Run the following code in R and select all answers that apply based on the code. I would also suggest running the code more than one as the numbers generated are random and results will vary slightly. CODE: #Generating datadata.exp = rexp(36)par(mfrow=c(2,1))hist(data.exp, main = 'Histogram of exponential with mean 1') #Gererate averages for the central limit theorem#I.e. data set of averagesbar = c(1:500)#store the averagesfor (i in c(1:500)) {data.exp = rexp(36)bar[i] = mean(data.exp)}hist(bar, main = 'Histogram of data set of averages for CLT') sprintf("Theoretical mean of data.exp: %s", 1)sprintf("mean of the average: %s", mean(bar))sprintf("Theoretical variance of data.exp: %s",…
Example-The Factorial Function To illustrate the operation of a for loop, we will use a for loop to calculate the factorial function. The factorial function is defined as n = 0 – 1) × (n – 2) × ... X 2x1 n>0 n! = (5.3) The MATLAB code to calculate N factorial for positive value of N would be n_factorial = 1 for ii = 1:n n_factorial = n_factorial * ii; end Suppose that we wish to calculate the value of 5!. If n is 5, the for loop control expression would be the row vector [1 2 3 4 5]. This loop will be executed 5 times, with the variable ii taking on values of 1, 2, 3, 4, and 5 in the successive loops. The resulting value of n_factorial will be 1 X 2 x 3 x 4 x 5 = 120. MATLAB includes a standard function called zactoriai to calculate the factorial function. Use the MATLAB help system to look up this function. Calculate 71, 141, and 21! using the program ini this example 7! = 14! = 21! = Calculate 7!, 14!, and 21! using the factorial function. 7! = 14! = 21! = How do the results compare?
Please solve using scilab, please add photo of code if possible. Existing answers on Bartleby are incorrect.
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Exercise 2: in scilab Write a code to plot the 2 signals: y1 = sin(t); y2 = sin(2*t) and their sum on an interval t = [-10, 10]. Use a step of 0.1 The 3 plots should be on the same figure on three rows (use subplot).