Exercise 2 Compete the table of ordered pairs for the equation 2x+3y=15. X -3 y 3 9 2(+3)+31/1 =15 =-6737=15

Algebra and Trigonometry (6th Edition)
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ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Exercise 2**

Complete the table of ordered pairs for the equation \(2x + 3y = 15\).

\[
\begin{array}{c|c}
x & y \\
\hline
-3 & \\
3 & \\
9 & \\
\end{array}
\]

**Solution Steps:**

1. Substitute \(x = -3\) into the equation: 
   \[
   2(-3) + 3y = 15 
   \]
   \[
   -6 + 3y = 15
   \]

2. Solve the equation for \(y\).

Continue this process to find the corresponding \(y\) values for each \(x\).
Transcribed Image Text:**Exercise 2** Complete the table of ordered pairs for the equation \(2x + 3y = 15\). \[ \begin{array}{c|c} x & y \\ \hline -3 & \\ 3 & \\ 9 & \\ \end{array} \] **Solution Steps:** 1. Substitute \(x = -3\) into the equation: \[ 2(-3) + 3y = 15 \] \[ -6 + 3y = 15 \] 2. Solve the equation for \(y\). Continue this process to find the corresponding \(y\) values for each \(x\).
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