Exercise 2: Calculate the wheel load stress at interior, edge and corner regions of a cement concrete pavement using Westergaard's stress equations, using from the following data: (i) Design wheel load = 4100 Kg (ii) E value of cement concrete = 3.3 x 10° Kg/cm2 (iii) Thickness of pavement slab = 18 cm %3D (iv) K = 25 kg/cm³, µ = 0.15 (v) Radius of contact area = 12 cm %3D

Exercise 2: Calculate the wheel load stress at interior, edge and corner regions of a cement concrete pavement using Westergaard's stress equations, using from the following data: (i) Design wheel load = 4100 Kg (ii) E value of cement concrete = 3.3 x 10° Kg/cm2 (iii) Thickness of pavement slab = 18 cm %3D (iv) K = 25 kg/cm³, µ = 0.15 (v) Radius of contact area = 12 cm %3D

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Measuring carpentry and miscellaneous items

The modification of planning and drawing of the construction project into the various descriptions and quantities to estimate the value, cost, and price of the project is known as measurement. The quantity supervisor produces the details of the quantities to the contractor or subcontractor to measure the cost of the work and determine the profit of the contractor or subcontractor. The measurement of the construction work depends on its type, usage, and stages in the project. In the early stage of the project, the details of the project depend on the general parameters. As the work starts, more information is searched and the details are dependent on the elemental estimates of the work.

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Exercise 2: Calculate the wheel load stress at interior, edge and corner regions of
a cement concrete pavement using Westergaard's stress equations, using from the
following data:
(i) Design wheel load = 4100 Kg
(ii) E value of cement concrete = 3.3 × 10° Kg/cm?
(iii) Thickness of pavement slab = 18 cm
(iv) K = 25 kg/cm³, µ = 0.15
(v) Radius of contact area =
12 cm

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