EXERCISE 2: Calculate the pH of a 0.50 M NH 3 at 25°C. At 25°C, the base dissociation constant (Kb) of ammonia (NH3) is 1.8 × 10-5. Step 1. Complete the ICE Table below: Hydrolysis Equation NH4+ (aq) NH3(aq) + H₂O(l) INITIAL 0.50 0 (Analytical molarity) CHANGE -X +X EQUILIBRIUM [NH3] [NH4*] = [OH-] = Step 2. Write the equilibrium expression for the base dissociation constant, K. Кь = Step 3. Substitute the mathematical equation containing the variable x into the equilibrium expression. Answer: Step 4 Calculate the value of [OH-]. Show the complete solution. SOLUTION Step 5. Calculate pH of the solution. Show the complete solution. Answer: + OH (aq) 0 +X

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EXERCISE 2: Calculate the pH of a 0.50 M NH3 at 25°C.
At 25°C, the base dissociation constant (Kb) of ammonia (NH3 ) is 1.8 × 10-5.
Step 1. Complete the ICE Table below:
NH4+ (aq)
Hydrolysis Equation
NH3(aq) + H₂O(1)
INITIAL
0.50
0
(Analytical molarity)
CHANGE
-X
+X
EQUILIBRIUM
[NH3]
[NHA] =
[OH-] =
Step 2. Write the equilibrium expression for the base dissociation constant, K
Kb =
Step 3. Substitute the mathematical equation containing the variable x into the equilibrium expression.
Answer:
Step 4 Calculate the value of [OH-]. Show the complete solution.
SOLUTION
Step 5. Calculate pH of the solution. Show the complete solution.
Answer:
X
+
OH (aq)
0
+X
Transcribed Image Text:EXERCISE 2: Calculate the pH of a 0.50 M NH3 at 25°C. At 25°C, the base dissociation constant (Kb) of ammonia (NH3 ) is 1.8 × 10-5. Step 1. Complete the ICE Table below: NH4+ (aq) Hydrolysis Equation NH3(aq) + H₂O(1) INITIAL 0.50 0 (Analytical molarity) CHANGE -X +X EQUILIBRIUM [NH3] [NHA] = [OH-] = Step 2. Write the equilibrium expression for the base dissociation constant, K Kb = Step 3. Substitute the mathematical equation containing the variable x into the equilibrium expression. Answer: Step 4 Calculate the value of [OH-]. Show the complete solution. SOLUTION Step 5. Calculate pH of the solution. Show the complete solution. Answer: X + OH (aq) 0 +X
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