Exercise 2 (Binary Search) Assume a binary search is performed on the following array of integers: {1, 14, 15, 24, 55, 59, 73, 90, 94, 99} Trace through each iteration of the algorithm, writing the number that will be the middle element and the left and right bounds (indexes), when searching for the number 73.
Exercise 2 (Binary Search) Assume a binary search is performed on the following array of integers: {1, 14, 15, 24, 55, 59, 73, 90, 94, 99} Trace through each iteration of the algorithm, writing the number that will be the middle element and the left and right bounds (indexes), when searching for the number 73.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Transcribed Image Text:Exercise 2 (Binary Search)
Assume a binary search is performed on the following array of integers:
{1, 14, 15, 24, 55, 59, 73, 90, 94, 99}
Trace through each iteration of the algorithm, writing the number that will be the middle
element and the left and right bounds (indexes), when searching for the number 73.
Explanation of the Binary Search Concept
Binary Search is an algorithm for finding a target element in a sorted linear collection. It
assumes that there exists a comparison relation between all elements in the collection that
allows for a total ordering of the elements. For example, integers can be compared by the less
than (<) operator. For Strings, we can order them lexicographically and compare using the
compareTo method. The key assumption is that the linear collection is already sorted before
binary search is applied.
The binary search algorithm is naturally defined recursively as follows:
if collection is empty, return -1 to indicate target is not found
Check if middle element is the target
if yes, then return its index
elsé:
if middle element is < target,
then return outcome of binary search on the elements to the right of the middle
else return outcome of binary search on the elements to the left of the middle
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