? Exercise 14.5.2 дz Az To calculate and for the following functions: Ju дv first calculate: Oz Ax ду ?x Ju 7у (x+3y)² = f(x,y) Z= 7у (x+3y)² -3e2u sin(3v) = 2x - y x+3y X = e2u cos 3v, y(u, v) =e2" sin 3v. , x(u, v) = "

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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? Exercise 14.5.2
дz Az
To calculate and for the following functions:
Ju дv
first calculate:
Oz
Ax
ду
?x
Ju
Ox
дv
ду
Ju
ду
дv
||
дz
дv
7у
(x+3y)2
= f(x,y)
Z=
7у
(x+3y)²
-3e2u sin(3v)
3e2u sin(3v)
0
=
2х-у
x+3y
21
(3sin(3v) + cos(3v))²
X
Then use the first formula above to find the partial derivative:
Oz
Ju
and use the second formula above to find:
X
, x(u, v) = = e2u cos 3v, y(u, v) = e²u sin 3v.
"
Transcribed Image Text:? Exercise 14.5.2 дz Az To calculate and for the following functions: Ju дv first calculate: Oz Ax ду ?x Ju Ox дv ду Ju ду дv || дz дv 7у (x+3y)2 = f(x,y) Z= 7у (x+3y)² -3e2u sin(3v) 3e2u sin(3v) 0 = 2х-у x+3y 21 (3sin(3v) + cos(3v))² X Then use the first formula above to find the partial derivative: Oz Ju and use the second formula above to find: X , x(u, v) = = e2u cos 3v, y(u, v) = e²u sin 3v. "
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