Exercise 11.5. Find: (1) gcd (x³-3x+2, x 4 + 4x² + 2x + 1) = Q[x]; (2) gcd (x³- 2x2 − x + 2, x² + 2x² + 1) € Z3[x]. -

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.2: Properties Of Division
Problem 16E
Question
Exercise 11.5. Find:
(1) gcd (x³-3x+2, x 4 + 4x² + 2x + 1) = Q[x];
(2) gcd (x³- 2x2 − x + 2, x² + 2x² + 1) € Z3[x].
-
Transcribed Image Text:Exercise 11.5. Find: (1) gcd (x³-3x+2, x 4 + 4x² + 2x + 1) = Q[x]; (2) gcd (x³- 2x2 − x + 2, x² + 2x² + 1) € Z3[x]. -
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