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Exercise 1.3.2. Here is a paraphrase of the exercise. Suppose that a and y are real numbers. Show that max{x,y} and = min{x,y} = x + y + x - y 2 - - x + y − |x − y\¸ 2

Exercise 1.3.2. Here is a paraphrase of the exercise. Suppose that a and y are real numbers. Show that max{x,y} and = min{x,y} = x + y + x - y 2 - - x + y − |x − y\¸ 2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please solve the following exercise with detailled explanations... I also provided a remark given to assist this proof. 

Exercise 1.3.2. Here is a paraphrase of the exercise. Suppose that and y are real numbers. Show that and max{x,y} = min{x,y} = x + y + x - y 2 x + y − |x − y\¸ - 2 Remarks If Exercise 1.2.10 had max and min in place of sup and inf, then the solution would be easy. The main difficulty in the exercise is that the suprema and the infima may not belong to the respective sets. Nonetheless, there must be elements in the sets within an arbitrarily small positive & of the suprema and the infima. The key to the proof is that establishing equality up to an arbitrarily small error is good enough. Exercise 1.3.2 is a standard application of the method of proof by cases. The trichotomy property of Definition 1.1.1 says that either a <y, or x = y, or > y. The upshot is that the "lattice" operations of maximum and minimum can be obtained from the operations of addition, multiplication, and absolute value.
Transcribed Image Text:Exercise 1.3.2. Here is a paraphrase of the exercise. Suppose that and y are real numbers. Show that and max{x,y} = min{x,y} = x + y + x - y 2 x + y − |x − y\¸ - 2 Remarks If Exercise 1.2.10 had max and min in place of sup and inf, then the solution would be easy. The main difficulty in the exercise is that the suprema and the infima may not belong to the respective sets. Nonetheless, there must be elements in the sets within an arbitrarily small positive & of the suprema and the infima. The key to the proof is that establishing equality up to an arbitrarily small error is good enough. Exercise 1.3.2 is a standard application of the method of proof by cases. The trichotomy property of Definition 1.1.1 says that either a <y, or x = y, or > y. The upshot is that the "lattice" operations of maximum and minimum can be obtained from the operations of addition, multiplication, and absolute value.
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