Exercise 1.2: Apply integration by parts a second time to get 272 2(1-2²) 2n x 2n 2(1-2²)-¹ sin(x2)dz = 2m ₁ [(1 – 2²)n-¹ – 22²(n − 1)(1 -- 2²)n-²] cos(xz)dz

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Exercise 1.2: Apply integration by parts a second time to get
2n
21A L =(1-
X
z(1-2²)-¹ sin(xz)dz =
2n
[(1-2²)-¹ -22² (n − 1)(1--2²2)^~²] cos(x2)dz
Transcribed Image Text:Exercise 1.2: Apply integration by parts a second time to get 2n 21A L =(1- X z(1-2²)-¹ sin(xz)dz = 2n [(1-2²)-¹ -22² (n − 1)(1--2²2)^~²] cos(x2)dz
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