Exercise 1.1: Apply integration by parts once to get 2n In(a) = [(1 - 2²)" cos(az)dz = ²" ["2(1-2²)-¹ sin(x2)dz x

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
Exercise 1.1: Apply integration by parts once to get
1₂ (2) = [₁ (1
In(3
11°2
1's *
#
3
13
$
(1-
fs
%
2n
2²)" cos(xz) az = ² ²01
2″ [z(1-2²)-¹ sin(xz)dz
40
01
5
A
4
4+
&
6 7
*
8
to
144
CO
ho
DII
O
C
Transcribed Image Text:Exercise 1.1: Apply integration by parts once to get 1₂ (2) = [₁ (1 In(3 11°2 1's * # 3 13 $ (1- fs % 2n 2²)" cos(xz) az = ² ²01 2″ [z(1-2²)-¹ sin(xz)dz 40 01 5 A 4 4+ & 6 7 * 8 to 144 CO ho DII O C
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