Exercise 1. Gio. At 25°C, the enthalpy of the following reaction is - 2205 kial N₂c9) + 3H₂g) - 2 NH3cg) us = -22.08 Kon "f1298" Alt, 29% = - 22.08 Kcal. Calculate the enthalpy of the reaction as a a function of the temperature knowing that the molar heats are: = 6.85 + 0,28 x107³ T CpN2,9) Cp (Wito, g) = 5.72 +8.96 x 103 T Cp (2, 3) = 6.65 +0.52 x10³ T We assume that there is no phase change in this temperature range. Please answer the question step-wise showing detailed explanations. Thankss in advenced !!!

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
f(x) =
Solution
0₁25 2²-1
1
0.251²-120
Exercise 1. Gio.
At 25°C, the enthalpy of the following reaction us - 2208 Kical
N2(g) + 3H₂(g)
J
2Niseg
st
12
1298 = -22.08 Kar
Alf1298 = -22.08 kcal.
Calculate the enthalpy of the reaction as a
a function of the
temperature knowing that the molar heats are:
Cp (№2,9).
= 6.85 + 0,28 X10
T
Cp (Wits; g) = 5.72 +8.96 x 10 3 7
Cp (2, 9)
We assume that there is no
6065 +0.52 x10³ T
af 12
phase change in this
temperature range,
Please answer the question step-wise showing
detailed explanations. Thanks in advanced !!!!
Kepada
Transcribed Image Text:f(x) = Solution 0₁25 2²-1 1 0.251²-120 Exercise 1. Gio. At 25°C, the enthalpy of the following reaction us - 2208 Kical N2(g) + 3H₂(g) J 2Niseg st 12 1298 = -22.08 Kar Alf1298 = -22.08 kcal. Calculate the enthalpy of the reaction as a a function of the temperature knowing that the molar heats are: Cp (№2,9). = 6.85 + 0,28 X10 T Cp (Wits; g) = 5.72 +8.96 x 10 3 7 Cp (2, 9) We assume that there is no 6065 +0.52 x10³ T af 12 phase change in this temperature range, Please answer the question step-wise showing detailed explanations. Thanks in advanced !!!! Kepada
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