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- C a p i t a l S t r u c t u r e : S t o c k V a l u a t i o n D e s c r i b e t h e e v e n t s t h a t o c c u r i n a n e f f i c i e n t m a r k e t i n r e s p o n s e t o n e w i n f o r m a t i o n t h a t c a u s e s t h e e x p e c t e d r e t u r n t o e x c e e d t h e r e q u i r e d r e t u r n . W h a t h a p p e n s t o t h e m a r k e t v a l u e ? W h a t d o e s t h e e f f i c i e n t - m a r k e t h y p o t h e s i s ( E M H ) s a y a b o u t ( a ) s e c u r i t i e s p r i c e s , ( b ) t h e i r r e a c t i o n t o n e w i n f o r m a t i o n , a n d ( c ) i n v e s t o r o p p o r t u n i t i e s t o p r o f i t ? W h a t i s t h e b e h a v i o r a l f i n a n c e c h a l l e n g e t o t h i s h y p o t h es i s ? D e s c r i b e t h e f r e e c a s h f l o w v a l u a t i o n m o d e l a n d e x p l a i n h o w i t d…Q30Question 8 If Listen == 1 tane√3 and 0 is in Quadrant II, what are sine and cose? A sine= == 2 cose = 1/1/1 B = sine, cose= √3 - 2 C √√√3 sine= cose = - 2 D sine = - 12 √√3 cose = 2
- 1 . W h a t a r e t h e r o l e s o f m a n a g e m e n t a n d t h e a u d i t o r i n t h e p r e p a r a t i o n a n d i n t e g r i t y o f t h e f i n a n c i a l s t a t e m e n t s ? 2 . W h y d o s o m e u n q u a l i f i e d o p i n i o n s h a v e e x p l a n a t o r y p a r a g r a p h s ? 3 . W i l l t h e a c c o u n t a n t e x p r e s s a n o p i n i o n o n r e v i e w e d f i n a n c i a l s t a t e m e n t s ? D e s c r i b e t h e a c c o u n t a n t ’ s r e p o r t f o r r e v i e w e d f i n a n c i a l s t a t e m e n t s . 4 . W h y a r e n o t e s t o s t a t e m e n t s n e c e s s a r y ? 5 . W h a t i s t h e r e l a t i o n s h i p b e t w e e n t h e a c c o u n t i n g e q u a t i o n a n d t h e d o u b l e - e n t r y s y s t e m o f r e c o r d i n g t r a n s a c t i o n s ?A n s w e r t h e f o l l o w i n g , y o u m a y f i n d t h e a n s w e r s i n a n y w e b s i t e a n d a l s o p u t a r e f e r e n c e T o p i c : F r i n g e B e n e f i t s T a x C o m p o n e n t s o f N o n - T a x a b l e F r i n g e B e n e f i t s C o m p o n e n t s o f D e - m i n i m i s B e n e f i t s C o m p o n e n t s o f U n s p e c i f i e d T a x a b l e f r i n g e b e n e f i t s N o t e : A n s w e r s h o u l d b e q u i t e l o n g f o r m e t o u n d e r s t a n d m o r e102. Four capacitors C1-1uF, C2=2uF, C3=3uF and C4-4uF are connected as given in figure. The potential of junction O is A. 16.5 V B. 18 V C. 15.5 V D. 18.5 V 10 V 5V C₁ # H C3+ CA 20 V 30 V
- 1. A-n-n-a- -M-a-r-i-e- -R-o-m--a-n- -r-e-c-e-n-t-l-y- -g-r-a-d-u-a-t-e-d- -f-r-o-m- -c-o-l-l-e-g-e- -a-n-d- -i-s- -e-v-a-l-u-a-t-i-n-g-- t-w-o- -c-r-e-d-i-t- -c-a-r-d-s-.- -C-a-r-d- -A- -h-a-s- -a-n-n-u-a-l- -f-e-e- -o-f P7,500 a-n-d- -a-n- -i-n-t-e-r-e-s-t- -r-a-t-e- -o-f 9%. C-a-r-d- -B- -h-a-s- -n-o- -a-n-n-u-a-l- -f-e-e- -a-n-d- -a-n- -i-n-t-e-r-e-s-t- -r-a-t-e- -o-f 16%. A-s-s-u-m-i-n-g- -t-h-a-t- -A-n-n-a- -M-a-r-i-e- -i-n-t-e-n-d-s- -t-o- -c-a-r-r-y- -n-o- -b-a-l-a-n-c-e- -a-n-d- -p-a-y- -o-f-f- -h-e-r- -c-h-a-r-g-e-s- -i-n- -f-u-l-l- -e-a-c-h- -m-o-n-t-h-,- -w-h-i-c-h- -c-a-r-d- -r-e-p-r-e-s-e-n-t-s- -t-h-e -b-e-t-t-e-r- -d-e-a-l-?- -I-f- -A-n-n-a- -M-a-r-i-e- e-x-p-e-c-t-e-d- -t-o- -c-a-r-r-y- -a- -s-i-g-n-i-f-i-c-a-n-t- -b-a-l-a-n-c-e- -f-r-o-m- -o-n-e- -m-o-n-t-h- -t-o- -t-h-e- -n-e-xt-,- -w-h-i-c-h- -c-ar-d- -w-o-u-l-d- -b-e- -b-e-t-t-e-r-?- -E-x-p-l-a-i-n- 2. -W-h-a-t- -i-s- -y-o-u-r- -o-p-i-n-i-o-n- -a-b-o-u-t- -u-s-i-n-g- -c-o-n-s-u-m-e-r-s- -l-o-a-n-s- -a-n-d-…Q7C a s e 1 . J a n e M c D o n a l d , a f i n a n c i a l a n a l y s t f o r C a r r o l l C o m p a n y , h a s p r e p a r e d t h e f o l l o w i n g s a l e s a n d c a s h d i s b u r s e m e n t e s t i m a t e s f o r t h e p e r i o d F e b r u a r y t o J u n e o f t h e c u r r e n t y e a r . M o n t h S a l e s C a s h d i s b u r s e m e n tF e b . $ 5 0 0 $ 4 0 0M a r c h 6 0 0 3 0 0A p r i l 4 0 0 6 0 0M a y 2 0 0 5 0 0J u n e 2 0 0 2 0 0 M c D o n a l d n o t e s t h a t h i s t o r i c a l l y , 3 0 % o f s a l e s h a v e b e e n f o r c a s h . O f c r e d i t s a l e s ,…
- T o p i c : B u s i n e s s V a l u a t i o n a n d C o r p o r a t e R e s t r u c t u r i n g D e f i n e a n d d i f f e r e n t i a t e a m o n g t h e m e m b e r s o f e a c h o f t h e f o l l o w i n g s e t s o f t e r m s : m e r g e r s , c o n s o l i d a t i o n s , a n d h o l d i n g c o m p a n i e s; a c q u i r i n g c o m p a n y a n d t a r g e t c o m p a n y ; f r i e n d l y m e r g e r a n d h o s t i l e m e r g e r ; a n d s t r a t e g i c m e r g e r a n d f i n a n c i a l m e r g e r.T o p i c : F i n a n c i a l A n a l y s i s G i v e t h r e e p o s s i b l e c a u s e s o f t h e f o l l o w i n g : A d v e r s e d i r e c t m a t e r i a l s p r i c e v a r i a n c e. F a v o r a b l e d i r e c t l a b o r r a t e v a r i a n c e . F a v o r a b l e d i r e c t m a t e r i a l s u s a g e v a r i a n c e. A d v e r s e d i r e c t l a b o r e f f i c i e n c y v a r i a n c e. A n d e x p l a i n ho w y o u w o u l d i d e n t i f y w h i c h v a ri a n c e s t o i n v e s t i g a t e N o t e : A n s w e r s s h o u l d b e q u i t e l o n g f o r m e t o u n d e r t a n d m o r e .myedio.com Question 12 Listen Use the function f(x)=2x-5 • Find the inverse of f(x). . . Graph f(x) and f(x) and state the domain of each function. Prove that f(x) and f¹(x) are inverses, both graphically and algebraically. ATTACHMENTS W Algebra2 U9 UnitTest_Q17 docx 146.32 KB
