Example. Show that the solution (if exists) is waigque Ue= Ś Unx t , sin (x) cos(at) o0 Unl0, t)- siüct) , Ux (T, t) = cos(t) , U(x, o) = cos ( ax) t>o ノ %3D 0くべく T.
Example. Show that the solution (if exists) is waigque Ue= Ś Unx t , sin (x) cos(at) o0 Unl0, t)- siüct) , Ux (T, t) = cos(t) , U(x, o) = cos ( ax) t>o ノ %3D 0くべく T.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![### Example
#### Show that the solution (if exists) is unique
Consider the following partial differential equation and boundary conditions:
\[
\begin{cases}
u_t = 5u_{xx} + \sin(x) \cos(2t), & 0 < x < \pi, t > 0 \\
u_x(0,t) = \sin(t), \quad u_x(\pi,t) = \cos(t), & t > 0 \\
u(x,0) = \cos(2x), & 0 < x < \pi
\end{cases}
\]
**Explanation:**
1. **Equation:** \( u_t = 5u_{xx} + \sin(x)\cos(2t) \)
- This is a second-order partial differential equation representing the evolution of a function \( u(x, t) \) over time \( t \) and space \( x \).
- The term \( u_t \) denotes the partial derivative of \( u \) with respect to time.
- The term \( u_{xx} \) denotes the second partial derivative of \( u \) with respect to space.
- The term \( \sin(x)\cos(2t) \) serves as a non-homogeneous source term in the equation.
2. **Boundary Conditions:**
- \( u_x(0,t) = \sin(t) \): This specifies the value of the spatial derivative of \( u \) at the left boundary \( x = 0 \) for any time \( t \).
- \( u_x(\pi,t) = \cos(t) \): This specifies the value of the spatial derivative of \( u \) at the right boundary \( x = \pi \) for any time \( t \).
3. **Initial Condition:**
- \( u(x,0) = \cos(2x) \): This provides the initial profile of \( u \) at time \( t = 0 \) across the spatial domain \( 0 < x < \pi \).
The task is to show that a unique solution exists for this PDE given the boundary and initial conditions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6dba997-101e-43e2-95cb-d4dc7d29171d%2Ffcccd182-8a9b-49fe-8f5d-9f407fbb2558%2Fmuj3fj4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Example
#### Show that the solution (if exists) is unique
Consider the following partial differential equation and boundary conditions:
\[
\begin{cases}
u_t = 5u_{xx} + \sin(x) \cos(2t), & 0 < x < \pi, t > 0 \\
u_x(0,t) = \sin(t), \quad u_x(\pi,t) = \cos(t), & t > 0 \\
u(x,0) = \cos(2x), & 0 < x < \pi
\end{cases}
\]
**Explanation:**
1. **Equation:** \( u_t = 5u_{xx} + \sin(x)\cos(2t) \)
- This is a second-order partial differential equation representing the evolution of a function \( u(x, t) \) over time \( t \) and space \( x \).
- The term \( u_t \) denotes the partial derivative of \( u \) with respect to time.
- The term \( u_{xx} \) denotes the second partial derivative of \( u \) with respect to space.
- The term \( \sin(x)\cos(2t) \) serves as a non-homogeneous source term in the equation.
2. **Boundary Conditions:**
- \( u_x(0,t) = \sin(t) \): This specifies the value of the spatial derivative of \( u \) at the left boundary \( x = 0 \) for any time \( t \).
- \( u_x(\pi,t) = \cos(t) \): This specifies the value of the spatial derivative of \( u \) at the right boundary \( x = \pi \) for any time \( t \).
3. **Initial Condition:**
- \( u(x,0) = \cos(2x) \): This provides the initial profile of \( u \) at time \( t = 0 \) across the spatial domain \( 0 < x < \pi \).
The task is to show that a unique solution exists for this PDE given the boundary and initial conditions.
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