EXAMPLE: The sum of any two even integers is even. Answer: Proof. (direct) Suppose x and y are even integers. By definition of even, let x = 2k and y = 2j for some integers j and k. Then, x+y=2k+2j = 2(k + j) Note that k+j is an integer because it is the sum of integers. Therefore, by definition of even, x + y is even. (a) For any integers x, y, and z with xy, if z is divisible by x-y, then z is divisible by y-x.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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EXAMPLE: The sum of any two even integers is even.
Answer:
Proof. (direct) Suppose x and y are even integers. By definition of even, let x = 2k and y = 2j for some
integers j and k. Then,
x+y=2k+2j = 2(k + j)
Note that k+j is an integer because it is the sum of integers. Therefore, by definition of even, x + y is
even.
Transcribed Image Text:EXAMPLE: The sum of any two even integers is even. Answer: Proof. (direct) Suppose x and y are even integers. By definition of even, let x = 2k and y = 2j for some integers j and k. Then, x+y=2k+2j = 2(k + j) Note that k+j is an integer because it is the sum of integers. Therefore, by definition of even, x + y is even.
(a) For any integers x, y, and z with xy, if z is divisible by x-y, then z is divisible by y-x.
Transcribed Image Text:(a) For any integers x, y, and z with xy, if z is divisible by x-y, then z is divisible by y-x.
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