Example Sample: NaCl+NaBr + inert = 1.000 g excess AGNO; U Ag: 107.87, Cl: 35.45 AgCl(s) + AgBr(s) = 0.5260 g Na: 22.99 Cl, treatment U AgCl(s) + AgCl(s) Br: 79.90 = 0.4260 g NaCl = ? % : NaBr= ? % %3D

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Example
Sample: NaC1+NaBr + inert
excess AGNO, U
= 1.000 g
Ag: 107.87,
Cl: 35.45
AgCl(s) + AgBr(s)
= 0.5260 g
Na:
22.99
Cl, treatment I
AgCl(s) + AgCl(s)
Br: 79.90
= 0.4260 g
Nacl = ? % : NaBr = ? %
Solution if NaCl=x g.
NaBr =y g
yx187.77
102.89
xx143.32
g of AgCl(s) =
: g of AgBr(s) =
58.44
xx143.32
yx187.77
+
xx100
= 0.5260 g
% NaCl =
58.44
102.89
1.000
xx143.32
ух143.32
= 0.4260 g
yx100
% NaBr =:
58.44
102.89
1.000
Transcribed Image Text:Homework Example Sample: NaC1+NaBr + inert excess AGNO, U = 1.000 g Ag: 107.87, Cl: 35.45 AgCl(s) + AgBr(s) = 0.5260 g Na: 22.99 Cl, treatment I AgCl(s) + AgCl(s) Br: 79.90 = 0.4260 g Nacl = ? % : NaBr = ? % Solution if NaCl=x g. NaBr =y g yx187.77 102.89 xx143.32 g of AgCl(s) = : g of AgBr(s) = 58.44 xx143.32 yx187.77 + xx100 = 0.5260 g % NaCl = 58.44 102.89 1.000 xx143.32 ух143.32 = 0.4260 g yx100 % NaBr =: 58.44 102.89 1.000
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