Ехample 31jear to year. If this variation of the mean mark is expressed subjectively by a normal distributionrk in mathematics in common entrance that willor If this variation of the mean mark is expressed subjectively by a normal distributionvary fromih mean Ho = .A What probability can we assign to the actual mean mark being somewhere between72 and variance o = 5.76.%3D71.8 and 73.4 for the next years test?G). Construct a 95% Bayesian interval for µ if the test is conducted for a randomsample of 100 students from the next incoming class yielding a mean mark of 70with s.d. of 8.(ii) What posterior probability should we assign to the event of part (i)

Answered: Image /qna-images/answer/3675d0ee-0e2f-4785-866f-0d2adcc60f5c.jpg

Answered: Example rto year. If this variation of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The "Select" parts are both (Normal / Binomial / Poisson).
age, a Bahand will last 6.3 days from the time it is purchased in the store to the time it is too rotten to eat. Is the mean time to spoil different if the banana is hung from the ceiling? The data show results of an experiment with 15 bananas that are hung from the ceiling. Assume that that distribution of the population is normal. 5.5, 3.9, 3.9, 5.7, 6.5, 5.9, 3.9, 7.4, 4.3, 5.9, 4.5, 4.2, 7, 5.1, 4 What can be concluded at the the a = 0.05 level of significance level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? Select an answer H₁: ? Select an answer c. The test statistic ? O (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) d. The p-value = e. The p-value is ? a f. Based on this, we should Select an answer the null hypothesis. g. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly different from 6.3 at a = 0.05, so there is…
8. (Topic 8) Suppose the average height of a two year old male is normally distributed with a mean of 34.2 inches and a standard deviation of 2.9 inches. Use this information to answer each part below. (a) What is the z-score associated with a two year old male that is 38 inches tall? Would this child be considered unusually tall for his age? (b) What is the z-score associated with a two year old male that is 28 inches tall? Would this child be considered unusually short for his age?
Which is not one of the major assumptions typically associated with parametric tests of significance? A. Random Selection B. Homogeneity of Variance C. Absence of restricted ranges
You are testing the claim that having lights on at night increases weight gain (abstract). A sample of 10 mice lived in an environment with bright light on all of the time and 8 mice who lived in an environment with a normal light/dark cycle is given below. Test the claim using a 10% level of significance. Assume the population variances are unequal and that the weight changes are normally distributed. Give answers to 3 decimal places. Data available at StatKey, choose Mice Wgt Gain-2e data set Light (x₁) 1.71 4.67 4.99 5.33 5.43 6.94 7.15 9.17 10.26 11.67 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: Select an answer ? V Select an answer V Ha: Select an answer ✓ Based on the hypotheses, find the following: Test Statistic = Dark (₂) 2.27 2.53 2.83 4 4.21 4.6 5.95 6.52 p-value = ? V Select an answer V (Hint: difference in means from Ha) The correct decision is to Select an answer…
8. Hypothesis Test of Equal Variances. Test the given claim. Use a significance level of a = 0.05 and assume that all populations are normally distributed. Claim: IQ scores of statistics students vary less than IQ scores of other students. Statistics students: n = 28, x = 118, s = 10.0 Other students: n = 25, x = 112, s = 12.0
Please answer the question contained in the following picture
Describe a scenario where a researcher could use an F-test for the equality of two variances to answer a research question.
Question Heip How do the requirements for a chi-square test for a variance or standard deviation differ from a z-test or a t-test for a mean? Choose the correct answer below. OA A chi-square test can only be used when the population has a normal distribution. On the other hand, a z-test or a t-test can only be used when the sample size is at least 30. O B. A chi-square test can only be used when the population has a normal distribution. On the other hand, a z-test or a t-test can be used when either the population has a normal distribution or the sample size is at least 30. O C. Az-test or a t-test can only be used when the population has a normal distribution. On the other hand, a chi-square test can be used when either the population has a normal distribution or the sample size is at least 30. O D. Az-test or a t-test can only be used when the population has a normal distribution. On the other hand, a chi-square test can only be used when the sample size is at least 30. Click to…
Mean = 5.2 Median=3 Mode= 2 Graph what the distribution would look like. Is it normally distributed? If not, how is it skewed and what might cause this type of skew to the distribution?
You are testing the claim that having lights on at night increases weight gain (abstract). A sample of 10 mice lived in an environment with bright light on all of the time and 8 mice who lived in an environment with a normal light/dark cycle is given below. Test the claim using a 2% level of significance. Assume the population variances are unequal and that the weight changes are normally distributed. Give answers to 3 decimal places. Data available at StatKey, choose Mice Wgt Gain-2e data set Light (1) 1.71 4.67 4.99 5.33 5.43 6.94 7.15 9.17 10.26 11.67 What are the correct hypotheses? Note this may view better in full screen mode. Select the correct symbols in the order they appear in the problem. Ho: ₁ Test Statistic = Dark (₂) 2.27 2.53 2.83 4 4.21 4.6 5.95 6.52 Ha: ₁ Based on the hypotheses, find the following: p-value = = V Select an answer ✓ Select an answer (Hint: difference in means from H₂) The correct decision is to fail to reject the null hypothesis The correct summary…
At a 0.05, test to see if the population variances from which the following samples were drawn are equal. The test statistic is Group 1 n₁ = 21 Group 2 n₂ = 19 $1 = 20 S2 = 18 (A) 1.56 (B) 1.23 (C) 1.26 (D) 1.11

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