EXAMPLE Problem 1 Coulomb's Law in Two Dimensions Sphere A, with a charge of +6.0 μC, is located near another charged sphere, B. Sphere B has a charge of -3.0 μC and is located 4.0 cm to the right of A. a. What is the force of sphere B on sphere A? b. A third sphere, C, with a +1.5-μC charge, is added to the configuration. If it is located 3.0 cm directly beneath A, what is the new net force on sphere A? Analyze and Sketch the Problem . Establish coordinate axes and sketch the spheres. +y Show and label the distances between A B the spheres. . Diagram and label the force vectors. q8 Known: Unknown: 9A= +6.0 μC AB= 4.0 cm FB on A = ? = 98 -3.0 μC ГАС = 3.0 cm FC on A = ? 9c = +1.5 μC Fnet = ? 2 Solve for the Unknown a. Find the force of sphere B on sphere A. FB on A = K² AB TAB +x FAC TAB QA qc 109 Nm² FC on

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### Example Problem 1: Coulomb’s Law in Two Dimensions

**Given:**
- **Sphere A:** Charge = +6.0 μC
- **Sphere B:** Charge = -3.0 μC, located 4.0 cm to the right of Sphere A
- **Sphere C:** Charge = +1.5 μC, located 3.0 cm directly beneath Sphere A

**Analyze and Sketch the Problem:**
1. **Establish Coordinate System:** Define +x and +y axes.
2. **Sketch the Spheres:**
   - Place Sphere A at the origin.
   - Position Sphere B 4.0 cm to the right of Sphere A along the x-axis.
   - Position Sphere C 3.0 cm directly beneath Sphere A along the y-axis.
3. **Label Distances and Forces:**
   - Distance \( r_{AB} \) between Sphere A and B: 4.0 cm
   - Distance \( r_{AC} \) between Sphere A and C: 3.0 cm
   - Represent force vectors \( F_{on\,A\,by\,B} \) and \( F_{on\,A\,by\,C} \)

**Diagram:**

```
  y-axis
    ↑
    |
    A (0,0)
    |\
    | \
rAC |  \
    |   \ 
    |    C (0, -3.0 cm)
    |
    +------→ x-axis
          4.0 cm
          B (4.0 cm, 0)
```

**Solve for the Unknown:**
- Find the force of Sphere B on Sphere A
- Find the force of Sphere C on Sphere A
- Determine the net force on Sphere A \( F_{net\,A}\)

### Steps:

**1. Calculate Forces Using Coulomb’s Law:**

The formula for Coulomb’s law is:
\[ F = k \frac{|q_1 q_2|}{r^2} \]

Where:
- \( k = 8.99 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2 \) (Coulomb's constant)
- \( q_1 \text{ and } q_2 \) are the charges
- \( r \) is the distance between the charges
Transcribed Image Text:### Example Problem 1: Coulomb’s Law in Two Dimensions **Given:** - **Sphere A:** Charge = +6.0 μC - **Sphere B:** Charge = -3.0 μC, located 4.0 cm to the right of Sphere A - **Sphere C:** Charge = +1.5 μC, located 3.0 cm directly beneath Sphere A **Analyze and Sketch the Problem:** 1. **Establish Coordinate System:** Define +x and +y axes. 2. **Sketch the Spheres:** - Place Sphere A at the origin. - Position Sphere B 4.0 cm to the right of Sphere A along the x-axis. - Position Sphere C 3.0 cm directly beneath Sphere A along the y-axis. 3. **Label Distances and Forces:** - Distance \( r_{AB} \) between Sphere A and B: 4.0 cm - Distance \( r_{AC} \) between Sphere A and C: 3.0 cm - Represent force vectors \( F_{on\,A\,by\,B} \) and \( F_{on\,A\,by\,C} \) **Diagram:** ``` y-axis ↑ | A (0,0) |\ | \ rAC | \ | \ | C (0, -3.0 cm) | +------→ x-axis 4.0 cm B (4.0 cm, 0) ``` **Solve for the Unknown:** - Find the force of Sphere B on Sphere A - Find the force of Sphere C on Sphere A - Determine the net force on Sphere A \( F_{net\,A}\) ### Steps: **1. Calculate Forces Using Coulomb’s Law:** The formula for Coulomb’s law is: \[ F = k \frac{|q_1 q_2|}{r^2} \] Where: - \( k = 8.99 \times 10^9 \, \text{N}\cdot\text{m}^2/\text{C}^2 \) (Coulomb's constant) - \( q_1 \text{ and } q_2 \) are the charges - \( r \) is the distance between the charges
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