Example: Let 4 1 S = Span| ui = 3 ,U4 = , u2 = ,u3 = , U5 = 1 -2 6 6. We find a row-echelon form of the matrix A = [u1 u2 u3 U4 U5]: 1 1 1 4 [1 1 1 4 1 3 7 1 -2 -1 1 -6 1 -2 -2 -4 1 -1 1 0 0 The pivot columns are columns x (enter your answer as a list of numbers in increasing numerical order, separated by commas but no spaces), so a basis for S is

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Example: Let
1
3
S = Span | ui =
, u3 =
, U5 =
U2 =
1
-6
U4 =
1
1
1
We find a row-echelon
form of the matrix A = [u1 u2 u3 U4 U5:
1
1
1
1
1
4
1
3
7
1
-2
-1
1
-6 1
-2
0 0
-2
-4
1
-1
6 1
0 0
The pivot columns are columns
x (enter your answer as a list of numbers in increasing numerical order, separated by commas but no spaces), so
a basis for S is
Transcribed Image Text:Example: Let 1 3 S = Span | ui = , u3 = , U5 = U2 = 1 -6 U4 = 1 1 1 We find a row-echelon form of the matrix A = [u1 u2 u3 U4 U5: 1 1 1 1 1 4 1 3 7 1 -2 -1 1 -6 1 -2 0 0 -2 -4 1 -1 6 1 0 0 The pivot columns are columns x (enter your answer as a list of numbers in increasing numerical order, separated by commas but no spaces), so a basis for S is
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