Example III page 8: 1. 5.17 g of fertilizer was added to a 250.0 mL volumetric flask and water was added to make it up to the mark. 2. 20.00 mL of this solution was pipetted into a conical flask. 3. A slight excess of precipitating agent was added to precipitate the phosphate ions as MgNH4PO4. 4. The precipitate was filtered, washed with water and then converted by heating into Mg2P207 5. The mass of Mg2P2O7 was 0.0312 g Calculate the percentage by mass of phosphate in the fertilizer. Ans%(PO4) = 6.42% Solution: mass of fertilizer = 5.17 g mass of Mg2P2O7 = 0.0312 g Total volume = 250.0 mL Used Volume = 20.00 mL 2 PO4³- Mg2P207 0.0312 g

Example III page 8: 1. 5.17 g of fertilizer was added to a 250.0 mL volumetric flask and water was added to make it up to the mark. 2. 20.00 mL of this solution was pipetted into a conical flask. 3. A slight excess of precipitating agent was added to precipitate the phosphate ions as MgNH4PO4. 4. The precipitate was filtered, washed with water and then converted by heating into Mg2P207 5. The mass of Mg2P2O7 was 0.0312 g Calculate the percentage by mass of phosphate in the fertilizer. Ans%(PO4) = 6.42% Solution: mass of fertilizer = 5.17 g mass of Mg2P2O7 = 0.0312 g Total volume = 250.0 mL Used Volume = 20.00 mL 2 PO4³- Mg2P207 0.0312 g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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