Example (H.W): A tube l cm inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2 - H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO, is 1.5 atm at one end of the tube and 0.5 atm at the other end, find the rate of diffusion for: i) Steady state equimolar counter diffusion (NA = - NB) ii) Steady state counter diffusion where NB -0.75 N A, and ii) Steady state diffusion of CO2 through stagnant H2 (NB = 0). un NB =

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question
100%
Mass transfer
101.3 - (1 – 3)0
In
2.0 X1U
1U1.3
NA
8.314 x 297 3.0 x 10-3 (1 – 3)
|101.3 – (1– 3)8.5
kmol
NA = 2.12 x 10-5
m2.s
Example (H.W): A tube 1 cm inside diameter that is 20 cm long is filled with CO2 and H2 at
a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2 - H2 system under these
conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and
0.5 ațm at the other end, find the rate of diffusion for:
i) Steady state equimolar counter diffusion (NA = - NB)
ii) Steady state counter diffusion where NB = -0.75 NA, and ana NB =
iii) Steady state diffusion of CO2 through stagnant H2 (NB = 0).
12
Transcribed Image Text:101.3 - (1 – 3)0 In 2.0 X1U 1U1.3 NA 8.314 x 297 3.0 x 10-3 (1 – 3) |101.3 – (1– 3)8.5 kmol NA = 2.12 x 10-5 m2.s Example (H.W): A tube 1 cm inside diameter that is 20 cm long is filled with CO2 and H2 at a total pressure of 2 atm at 0°C. The diffusion coefficient of the CO2 - H2 system under these conditions is 0.275 cm2/sec. If the partial pressure of CO2 is 1.5 atm at one end of the tube and 0.5 ațm at the other end, find the rate of diffusion for: i) Steady state equimolar counter diffusion (NA = - NB) ii) Steady state counter diffusion where NB = -0.75 NA, and ana NB = iii) Steady state diffusion of CO2 through stagnant H2 (NB = 0). 12
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