Example Frequency Distribution & Histogram The data represent the time, in minutes, spent reading a political blog in a day (sorted). Construct a frequency distribution using 5 classes. Solution: The smallest value in the data set is 0 and the largest is 39. We want 5 classes, so we find the class width with the formula: Approx. class width = max-min # of classes = 39-0 5 = 7.8 0 9 21 31 3 14 21 31 3 16 23 32 4 17 25 37 5 18 26 39 NOTE: round up to the next whole number and use a class width of 8. Class boundaries for integer data-subtract 0.5 from the lower class limit and add 0.5 to the upper class limit. Class midpoint -the average of the lower and upper limits of the class. Class Class Boundaries Midpoint Frequency Relative Cumulative Frequency Frequency Example Frequency Distribution & Histogram The data represent the time, in minutes, spent reading a political blog in a day (sorted). Construct a frequency distribution using 5 classes, =20 Solution: The smallest value in the data set is 0 and the largest is 39. We want 5 classes, so we find the class width with the formula: Approx.class width = max - min # of classes 39 20-78 B 21 32 14 21 31 16 28 32 17 25 37 5 18 26 39 NOTE: round up to the next whole number and use a class width of 8. Class boundaries for integer data-subtract 0.5 from the lower class limit and add 0.58 to the upper class limit. Class midpoint -the average of the lower and upper limits of the class. Class Class Boundaries Midpoint Frequency Relative Cumulative Frequency Frequency 0-7.5-7.5 3.5 5 5/2=-25 5 16. Q 15 7.5 15.5 145 22/20=-107 23 15.5-23.5 19.5 6 6/203.30 13 24-31 235-31.5 27.5 42.2017 32-39 325-39.5 35.5 3 3/20-25 20 2012
Example Frequency Distribution & Histogram The data represent the time, in minutes, spent reading a political blog in a day (sorted). Construct a frequency distribution using 5 classes. Solution: The smallest value in the data set is 0 and the largest is 39. We want 5 classes, so we find the class width with the formula: Approx. class width = max-min # of classes = 39-0 5 = 7.8 0 9 21 31 3 14 21 31 3 16 23 32 4 17 25 37 5 18 26 39 NOTE: round up to the next whole number and use a class width of 8. Class boundaries for integer data-subtract 0.5 from the lower class limit and add 0.5 to the upper class limit. Class midpoint -the average of the lower and upper limits of the class. Class Class Boundaries Midpoint Frequency Relative Cumulative Frequency Frequency Example Frequency Distribution & Histogram The data represent the time, in minutes, spent reading a political blog in a day (sorted). Construct a frequency distribution using 5 classes, =20 Solution: The smallest value in the data set is 0 and the largest is 39. We want 5 classes, so we find the class width with the formula: Approx.class width = max - min # of classes 39 20-78 B 21 32 14 21 31 16 28 32 17 25 37 5 18 26 39 NOTE: round up to the next whole number and use a class width of 8. Class boundaries for integer data-subtract 0.5 from the lower class limit and add 0.58 to the upper class limit. Class midpoint -the average of the lower and upper limits of the class. Class Class Boundaries Midpoint Frequency Relative Cumulative Frequency Frequency 0-7.5-7.5 3.5 5 5/2=-25 5 16. Q 15 7.5 15.5 145 22/20=-107 23 15.5-23.5 19.5 6 6/203.30 13 24-31 235-31.5 27.5 42.2017 32-39 325-39.5 35.5 3 3/20-25 20 2012
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Frequency Distribution & Histogram chart: Answers are already provided except last row, Explain how to solve for class, class boundaries, midpoint, frequency, relative frequency and culmulative frequency in each column. Show all steps.
Transcribed Image Text:Example Frequency Distribution & Histogram
The data represent the time, in minutes, spent reading a political blog
in a day (sorted). Construct a frequency distribution using 5 classes.
Solution: The smallest value in the data set is 0 and the largest is 39.
We want 5 classes, so we find the class width with the formula:
Approx. class width =
max-min
# of classes
=
39-0
5
= 7.8
0
9
21
31
3
14 21
31
3
16
23
32
4
17
25
37
5
18
26 39
NOTE: round up to the next whole
number and use a class width of 8.
Class boundaries for integer
data-subtract 0.5 from the
lower class limit and add 0.5
to the upper class limit.
Class midpoint -the average
of the lower and upper limits
of the class.
Class
Class Boundaries
Midpoint Frequency
Relative Cumulative
Frequency Frequency
Transcribed Image Text:Example Frequency Distribution & Histogram
The data represent the time, in minutes, spent reading a political blog
in a day (sorted). Construct a frequency distribution using 5 classes,
=20
Solution: The smallest value in the data set is 0 and the largest is 39.
We want 5 classes, so we find the class width with the formula:
Approx.class width =
max - min
# of classes
39
20-78
B
21 32
14 21 31
16 28 32
17 25 37
5 18 26 39
NOTE: round up to the next whole
number and use a class width of 8.
Class boundaries for integer
data-subtract 0.5 from the
lower class limit and add 0.58
to the upper class limit.
Class midpoint -the average
of the lower and upper limits
of the class.
Class
Class Boundaries
Midpoint Frequency
Relative Cumulative
Frequency Frequency
0-7.5-7.5 3.5 5 5/2=-25 5
16.
Q
15 7.5 15.5 145 22/20=-107
23 15.5-23.5 19.5 6 6/203.30 13
24-31 235-31.5 27.5 42.2017
32-39 325-39.5 35.5 3 3/20-25 20
2012
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