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Example : For the following traffic composition Passenger car Busses (>25 passenger) Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =5% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) = 8500* (05/100) = 425 No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 %3D = 8500* (42/100) = 4570 = 8500* (03/100) = 255 %3D 4250*1+ 425*2.5+3570*3+255*0.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU %3D Activate Wind Go to Settings to

Example : For the following traffic composition Passenger car Busses (>25 passenger) Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =5% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) = 8500* (05/100) = 425 No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 %3D = 8500* (42/100) = 4570 = 8500* (03/100) = 255 %3D 4250*1+ 425*2.5+3570*3+255*0.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU %3D Activate Wind Go to Settings to

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Example : For the following traffic composition Passenger car Busses (>25 passenger) =5% Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 = 8500* (05/100) = 425 = 8500* (42/100) = 4570 = 8500* (03/100) = 255 4250*1+ 425*2.5+3570*3+255*0.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU Activate Windows Go to Settings to activate
Transcribed Image Text:Example : For the following traffic composition Passenger car Busses (>25 passenger) =5% Heavy vehicle motorcycle Determine the equivalent passenger car unit if the total number of vehicles passing is 8500 veh. =50% =42% =3% Solution: No. Passenger cars No. of busses (25 passenger) No. heavy vehicle No. of motorcycle Total equivalent passenger car = = 8500* (50/100) = 4250 = 8500* (05/100) = 425 = 8500* (42/100) = 4570 = 8500* (03/100) = 255 4250*1+ 425*2.5+3570*3+255*0.33 Total equivalent passenger car = 4250+1062.5+10710+84.15 = 16107 PCU Activate Windows Go to Settings to activate
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