Example: Find the magnetic field due to wire A'ACC' at O, which is the center of a circular arc carrying current i. Given are: i, R and 0.
Example: Find the magnetic field due to wire A'ACC' at O, which is the center of a circular arc carrying current i. Given are: i, R and 0.
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in this completed example, why is r equal to sintheta? Also the integration is dtheta, how do we get there?

Transcribed Image Text:Example: Find the magnetic field due to wire A'ACC' at O, which is the center of a circular arc
carrying current i. Given are: i, R and 0.
For the arc segment AC:
The magnetic field due to segments AA' and CC' is zero because
ds xf =
(ds) (sin0) = 0
where is in radians!
B =
Moi
4πR²
dB =
dB =
So
B
ds =
Mo i ds x f
4π r2
-
Ho i ds sin90
4π
R²
Moi
4πR²
Ꮎ
Soº
For a circular wire, 0 = 2π, and the magnetic field at the center of the loop is:
μοί
μοί
4πR
2R
(2π)
Rd0 =
=
Hoi
4πR
Ꮎ .
R
C
i
C'
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