Example: A (1.84 N) body is suspended by a spring which is stretched (15.3 cm) when it is loaded. If the body is drawn down (10 cm) from the position of time (1) if: equilibrium; find the position of the spring as a function of 1. e-1.5 2. c= 3.75 3. c=3 Solution: M y"+c y'+k y = 0 W 1.84 9.8 M 0.188 Ag 1.84 - 15.3 cm 5. 0.153 10 cm 1) for e-1.5 L84 0.188y"-1.5y'+12 y-0 y"+8y'+64 y = 0 m +8m + 64 = 0 – 87 v64 – 4× 64 Dashpot 44/31 o Under Damping 2 v)"(Acos4/3 t+ Bsin 4/3t) Initial Conamo at 1=0 y'=o y=0.lm y(0) = A+0=0.1 = A=0.1 y0)--45 Asin 4/31+4/5 Beos45 ] [tcos4/3+ Bsin4/5-4e") y(0) = 45 B-4A= 4/3 B -4x0.1=0 = B-
Example: A (1.84 N) body is suspended by a spring which is stretched (15.3 cm) when it is loaded. If the body is drawn down (10 cm) from the position of time (1) if: equilibrium; find the position of the spring as a function of 1. e-1.5 2. c= 3.75 3. c=3 Solution: M y"+c y'+k y = 0 W 1.84 9.8 M 0.188 Ag 1.84 - 15.3 cm 5. 0.153 10 cm 1) for e-1.5 L84 0.188y"-1.5y'+12 y-0 y"+8y'+64 y = 0 m +8m + 64 = 0 – 87 v64 – 4× 64 Dashpot 44/31 o Under Damping 2 v)"(Acos4/3 t+ Bsin 4/3t) Initial Conamo at 1=0 y'=o y=0.lm y(0) = A+0=0.1 = A=0.1 y0)--45 Asin 4/31+4/5 Beos45 ] [tcos4/3+ Bsin4/5-4e") y(0) = 45 B-4A= 4/3 B -4x0.1=0 = B-
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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