Example 7.5: An isosceles prism of refracting angle 179° and refractive index 1.5 is used as a biprism by keeping it 10 cm away from a slit, the edge of the biprism being parallel to the slit. The slit is illuminated by a light of wavelength 500 nm and the screen is 90 cm away from the biprism. Calculate the location of the centre of 20th dark band and the path difference at this location. Solution: From the figure, S₁ A = 0.5° d/4 8/2 d S S₂ 179 -X- A=0.5° Xx₂-
Example 7.5: An isosceles prism of refracting angle 179° and refractive index 1.5 is used as a biprism by keeping it 10 cm away from a slit, the edge of the biprism being parallel to the slit. The slit is illuminated by a light of wavelength 500 nm and the screen is 90 cm away from the biprism. Calculate the location of the centre of 20th dark band and the path difference at this location. Solution: From the figure, S₁ A = 0.5° d/4 8/2 d S S₂ 179 -X- A=0.5° Xx₂-
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Please can you send me the solution of the attached problem below
Transcribed Image Text:Example 7.5: An isosceles prism of
refracting angle 179° and refractive index
1.5 is used as a biprism by keeping it
10 cm away from a slit, the edge of the
biprism being parallel to the slit. The slit
is illuminated by a light of wavelength 500
nm and the screen is 90 cm away from the
biprism. Calculate the location of the centre
of 20th dark band and the path difference at
this location.
Solution: From the figure,
S₁
d/4 8/2
d
S
S₂
179
di
←X₁
A = 0.5°
A=0.5
X₂-
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