Please explain how we got number 6/61 in example one and example two _1/36......... thank you very much Example 7: Find the solution of i + 2ý + 4y = x cos 3xThe chr. Eq. is r2 + 2r + 4 = 0-b+ vb? - 4acr1,2=2a12- -1+ iv3yc = c,e* cos v3x + cze sin v3xyp = (Ax + B)cos 3x + (Cx + D) sin 3x)yp = (A)cos3x + (Ax + B)(-3sin3x) + (C)(sin 3x)+(Cx+D)(3cos3x)ўр ——ЗAsin 3х + (A)(-3sin3х) + (Ах+ B)(-9 cos 3x) + 3C cos3x+ C(3 cos 3x) + (CX + D)(-9 sin 3x)654-sin3x +3721382yp =sin 3x- cos 3x +3721 Cos3x61Example 8: Find the solution of i - 4ý – 12y = xe4xSol:The chr. Eq. is r2 – 4r – 12 = 0(r - 6)(r + 2) = 0 -r, = 6,r, = -2y = c,e"* + c,e"*yc = c,e6x + cze-2yp = (Ax + B)e 4xýp = Ae ** + 4(Ax + B)e1*ÿp = 4Ae* + 4Ae* + 16(Ax + B)e**-12A-1, A-1/10 , Jalauxe+*4A-12B=0, Joles e 4x B=-1/36ур36e(3x + 1)

“Since you have asked multiple question, we will solve the first question for you. If youwant any…

Example 7: Find the solution of y + 2ý + 4y =x cos 3x The chr. Eq. is r? + 2r + 4 = 0 -bt vb2 - 4ac 2a yc = c,e* cos v3x + cze" sin v3x yp = (Ax + B)cos 3x + (Cx + D) sin 3x) yp = (A)cos3x + (Ax + B)(-3sin3x) + (C)(sin 3x)+(Cx+D)(3cos3x) ỹp = -3Asin 3x + (A)(-3sin3x) + (Ax + B)(-9 cos 3x) + 3C cos3x + C(3 cos 3x) + (CX + D)(-9 sin 3x) 5 sin 3x 61 54 sin3x + 3721 382 cos3x 3721 yp = 61 Cos 3x +

Example 7: Find the solution of y + 2ý + 4y =x cos 3x The chr. Eq. is r? + 2r + 4 = 0 -bt vb2 - 4ac 2a yc = c,e* cos v3x + cze" sin v3x yp = (Ax + B)cos 3x + (Cx + D) sin 3x) yp = (A)cos3x + (Ax + B)(-3sin3x) + (C)(sin 3x)+(Cx+D)(3cos3x) ỹp = -3Asin 3x + (A)(-3sin3x) + (Ax + B)(-9 cos 3x) + 3C cos3x + C(3 cos 3x) + (CX + D)(-9 sin 3x) 5 sin 3x 61 54 sin3x + 3721 382 cos3x 3721 yp = 61 Cos 3x +

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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