Example 7: Find (a) the rank and nullity of A and (b) a subset of the column vectors of A that forms a basis for the column space of A. -2 -4 4 6. -6 -4 -2 -4 4 9.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Example 7:** Find (a) the rank and nullity of \( A \) and (b) a subset of the column vectors of \( A \) that forms a basis for the column space of \( A \).

\[
A = \begin{bmatrix} 
-2 & -4 & 4 & 5 \\ 
3 & 6 & -6 & -4 \\ 
-2 & -4 & 4 & 9 
\end{bmatrix}
\]

**Explanation for Educational Context:**

In this example, matrix \( A \) is a \( 3 \times 4 \) matrix. The problem is asking to determine:

a) The **rank** of \( A \), which is the dimension of the column space of \( A \) (the number of linearly independent columns), and the **nullity** of \( A \), which is the dimension of the null space of \( A \) (the number of linearly independent solutions to the homogeneous equation \( A\mathbf{x} = 0 \)).

b) A subset of the columns of \( A \) that forms a basis for the column space of \( A \), indicating which columns are linearly independent and span the same space as all columns of \( A \).
Transcribed Image Text:**Example 7:** Find (a) the rank and nullity of \( A \) and (b) a subset of the column vectors of \( A \) that forms a basis for the column space of \( A \). \[ A = \begin{bmatrix} -2 & -4 & 4 & 5 \\ 3 & 6 & -6 & -4 \\ -2 & -4 & 4 & 9 \end{bmatrix} \] **Explanation for Educational Context:** In this example, matrix \( A \) is a \( 3 \times 4 \) matrix. The problem is asking to determine: a) The **rank** of \( A \), which is the dimension of the column space of \( A \) (the number of linearly independent columns), and the **nullity** of \( A \), which is the dimension of the null space of \( A \) (the number of linearly independent solutions to the homogeneous equation \( A\mathbf{x} = 0 \)). b) A subset of the columns of \( A \) that forms a basis for the column space of \( A \), indicating which columns are linearly independent and span the same space as all columns of \( A \).
Expert Solution
Step 1

The given matrix is:

           A=-2-44536-6-4-2-445

To find rank and nullity of matrix, first we will find the ow reduced echelon form of matrix.

Now applying R1R1+R2:

A12-2136-6-4-2-445

now applying 

R2R2-3R1R3R3+2R1

A12-21000-70007

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