Example 7-3. If the BOD, of a waste is 75 mg/L and the K is 0.150 d', what is the ultimate BOD?

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Example 7-3. If the BOD, of a waste is 75 mg/L and the K is 0.150 d', what is the
ultimate BOD?
Solution. Note that the rate constant is given in base 10 (K versus k), and substitute
tle given valucs into Equativu 7-5 anl sulve foi L.
75 = L(1 – 10-(150K3)) = 0.645 L,
or
75
= 116 or 120 mg/L
L =
0.645
In base e,
k = 2.303(K) = 0.345, and
75 = L(1 - e-(345K3)) = 0.645 L,
SO
L, = 116 or 120 mg/L
Comment: Because two significant figures were used to report the 3-day BOD, the
calculated ultimate BOD is reported to two significant figures.
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Transcribed Image Text:2:27 (77 Today 2:22 PM Example 7-3. If the BOD, of a waste is 75 mg/L and the K is 0.150 d', what is the ultimate BOD? Solution. Note that the rate constant is given in base 10 (K versus k), and substitute tle given valucs into Equativu 7-5 anl sulve foi L. 75 = L(1 – 10-(150K3)) = 0.645 L, or 75 = 116 or 120 mg/L L = 0.645 In base e, k = 2.303(K) = 0.345, and 75 = L(1 - e-(345K3)) = 0.645 L, SO L, = 116 or 120 mg/L Comment: Because two significant figures were used to report the 3-day BOD, the calculated ultimate BOD is reported to two significant figures. Send Favorite Edit Delete More
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