Example 6 to An amount of energy equal to 100 J is used in 5 s. What is the power Solution P = W/ t =100 J/5 sec = 20 W Example 7 What power is dissipated in a 100 Q resistor with 5 V across it? Solution v2 P = R (5)2 = 0.25 W %D %3D 100
Example 6 to An amount of energy equal to 100 J is used in 5 s. What is the power Solution P = W/ t =100 J/5 sec = 20 W Example 7 What power is dissipated in a 100 Q resistor with 5 V across it? Solution v2 P = R (5)2 = 0.25 W %D %3D 100
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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