Example 5.32The total revenue from the sale of the three grades of gasoline on a particular day wasY = 3.0X₁ + 3.2X₂ + 3.4X3, and it was determined that y = 5620 and (assuming independence)If the X's are ---Select---distributed, the probability that revenue exceeds 4300 isp(Y> []) = P(Z >43005620429.46= P(Z > -3.07) = 1- $(1= 0.9989.= 429.46.

The mean is 5620 and the standard deviation is 429.46.

Answered: Example 5.32 The total revenue from the…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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