Example 5.1 Suppose a student has secured the following marks in three tests: Mid-term test 30 Laboratory 25 Final 20 30+ 25 + 20 The simple arithmetic mean will be = 25 3 However, this will be wrong if the three tests carry different weights on the basis of their relativ importance. Assuming that the weights assigned to the three tests are: Mid-term test Laboratory Final 2 points 3 points 5 points
Example 5.1 Suppose a student has secured the following marks in three tests: Mid-term test 30 Laboratory 25 Final 20 30+ 25 + 20 The simple arithmetic mean will be = 25 3 However, this will be wrong if the three tests carry different weights on the basis of their relativ importance. Assuming that the weights assigned to the three tests are: Mid-term test Laboratory Final 2 points 3 points 5 points
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.1: Measures Of Center
Problem 23PFA
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![Example 5.1 Suppose a student has secured the following marks in three tests:
Mid-term test
30
Laboratory
25
Final
20
30+ 25+ 20
The simple arithmetic mean will be
= 25
3
However, this will be wrong if the three tests carry different weights on the basis of their relative
importance. Assuming that the weights assigned to the three tests are:
Mid-term test
2 points
3 points
5 points
Laboratory
Final](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47570ea3-6c8a-4bd1-a05f-43d4f7743b12%2Fe1cf00e0-71fb-43ff-847d-3bb529d065a9%2Fvldeabsd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Example 5.1 Suppose a student has secured the following marks in three tests:
Mid-term test
30
Laboratory
25
Final
20
30+ 25+ 20
The simple arithmetic mean will be
= 25
3
However, this will be wrong if the three tests carry different weights on the basis of their relative
importance. Assuming that the weights assigned to the three tests are:
Mid-term test
2 points
3 points
5 points
Laboratory
Final
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