Example 5 Mean of a binomial distribution is 20 and the variance is 16. Calculaten, pandq
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- Analysis of variance compares the means of a response variable for several groups. ANOVA compares the variation within each group to the variation of the mean of each group. The ratio of these two is the F statistic from an F distribution with (number of groups - 1) as the numerator degrees of freedom and (number of observations - number of groups) as the denominator degrees of freedom.You intend to conduct an ANOVA with 4 groups in which each group will have the same number of subjects: n=12n=12. (This is referred to as a "balanced" single-factor ANOVA.)What are the degrees of freedom for the numerator?d.f.(treatment) = What are the degrees of freedom for the denominator?d.f.(error) =analysis of variance, differences caused by treatment effects contribute to which of the n an following types of variance?Microsoft Edge 3 https://elearn.squ.edu.om/mod/quiz/attempt.php?attempt3D1894461&cmid3890604&page=12 QU E-LEARNING SYSTEM (ACADEMIC) Business Statistics 1 || Spring21 Time left 1:46:05 Quiz Question 13 The total cost for a production process is $600 minus two times the number of units produced. The mean and variance of the number of produced are 200 and 20, respectively. So, the mean and variance of the total cost are ot yet swered arked out of a. 600, 200 Nu 1 Flag estion ОБ. 400, 180 O c. 1000, 560 O d. 200, 80 NEXT PAGE PREVIOUS PAGE
- Pls do fast its urgent and i will rate instantly for sure Solution must be in typed formAnalysis of variance compares the means of a response variable for several groups. ANOVA compares the variation within each group to the variation of the mean of each group. The ratio of these two is the F statistic from an F distribution with (number of groups - 1) as the numerator degrees of freedom and (number of observations - number of groups) as the denominator degrees of freedom.You intend to conduct an ANOVA with 7 groups in which each group will have the same number of subjects: n=16n=16. (This is referred to as a "balanced" single-factor ANOVA.)What are the degrees of freedom for the numerator?d.f.(treatment) = What are the degrees of freedom for the denominator?d.f.(error) =How much number is trials if a Binomial distribution has mean of 7 and variance 6
- Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year x1 = 75.8 | x,= 76.2 si= 47.61 s3= = 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…Actuaries use various parameters when evaluating the cost of a life insurance policy. The variance of the life spans of a population is one of the parameters used for the evaluation. Each year, the actuaries at a particular insurance company randomly sample 30 people who died during the year (with the samples chosen independently from year to year) to see whether the variance of life spans has changed. The life span data from this year and from last year are summarized below. Current Last Year Year *1 = 75.8 x2 = 76.2 s3 = 47.61 s3= 92.16 (The first row gives the sample means and the second row gives the sample variances.) Assume that life spans are approximately normally distributed for each of the populations of people who died this year and people who died last year. Can we conclude, at the 0.05 significance level, that the variance of the life span for the current year, of, differs from the variance of the life span for last year, o,? Perform a two-tailed test. Then complete the…Part 1. .If b = 0.523, then for every 1 unit increase in the independent variable, there is a 0.523 unit increase in the dependent variable. True or false? 2. .If b = .704, then 70.4% of the variance in the dependent variable can be explained by the variance in the independent variable. In contrast, 29.6% of the variance in the dependent variable can be explained by outside factors. True or false? 3. .If r = 0.444, then for every 1 unit increase in the independent variable, there is a 0.444 unit increase in the dependent variable. True or false?