EXAMPLE 5 Find: (a) (V5? (b) (2i/7x?) (e) (8- v3)° (d) (Vm+1+2)°. Strategy In part (a), we will use the definition of square root. In part (b), we will use a power rule for exponents. In parts (c) and (d), we will use the FOIL method. Why Part (a) is the square of a square root, part (b) has the form (xy)", and part (c) has the form (x + y)². (V5)? =Ox Solution (а) Because the square of the square root of 5 is 5. (21 7)'. (b) We can use the power of a product rule for exponents to find (21/7)' - 2{(V/7)' Raise each factor of 27x to the 3rd power. (Ox )(7x²) Evaluate: 23 = 8. Use = a. = 56x? Multiply: 8. 7 = 56 () (8 - v3) - (8 - v3)(s - v3) Write the base 8 - V3 as a factor twice. = 64 – 8/3 - 8/3 + /3/3 Use the FOIL method = 64 - 16/3 + 3 = 67 - 16/3 Combine like radicals: -8/3 - 8y3 = -16/3. Combine like terms: 64 + 3 = 67. (8 - v3) Success Tip Since has the form (x - y)?, we could also use special product rule to find this square of a difference quickly. (d) We can use the FOIL method to find the product. (/m + 1 + 2)? = (Vm + 1 + 2)(/m+ 1 + 2) m+ + 2/m + 1 + 2/m + 1 + 2 · 2 %3D = m +1+ 2/ m + 1 + 2/m + 1 +Ox Use = a. = m + 4V m + 1 +| ...... Combine like terms.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
EXAMPLE 5 Find: (a)
(V5? (b) (2/7) (c) (8 - v3) (4)
(Vm + 1 + 2)*.
27x2
(d)
Strategy
In part (a), we will use the definition of square root. In part (b), we will use a power rule for exponents. In parts (c) and (d), we will use the FOIL method.
Why
Part (a) is the square of a square root, part (b) has the form (xy)", and part (c) has the form (x + y)².
Solution
(a)
(V5)2
Because the square of the square root of 5 is 5.
(b)
We can use the power of a product rule for exponents to find (2V 7x2 ).
(2i/72)' = '
3
2°(V7x2)
Raise each factor of 27x? to the 3rd power.
(Ox )(7x2) Evaluate: 23 = 8. Use
(v5)" =
= a.
= 56x2
Multiply: 8 ·
7 = 56
(6) (3 - V3)° - (8 - v3)(8 - v3)
2
– V3
V3
(c)
Write the base 8
3 as a factor twice.
%D
64 – 8V3 - 8/3 + V3 V 3 Use the FOIL method
%3D
= 64 – 16V3 + 3
Combine like radicals: -8/3 - 8/3 = -16/3.
= 67 – 16/3
Combine like terms: 64 + 3 = 67.
Success Tip
2
(8 - v3)*
Since
has the form (x – y)², we could also use a special product rule to find this square of a difference quickly.
(d)
We can use the FOIL method to find the product.
(/m + 1 + 2)? = (Vm + 1 + 2)(/
m + 1 + 2
- (vm + 1)*
+ 2/ m + 1 + 2/m + 1 + 2· 2
=
= m + 1 + 2/ m + 1 + 2Vm + 1 + X
(va)" =
Use
= a.
= m + 4V m + 1 +
Combine like terms.
Transcribed Image Text:EXAMPLE 5 Find: (a) (V5? (b) (2/7) (c) (8 - v3) (4) (Vm + 1 + 2)*. 27x2 (d) Strategy In part (a), we will use the definition of square root. In part (b), we will use a power rule for exponents. In parts (c) and (d), we will use the FOIL method. Why Part (a) is the square of a square root, part (b) has the form (xy)", and part (c) has the form (x + y)². Solution (a) (V5)2 Because the square of the square root of 5 is 5. (b) We can use the power of a product rule for exponents to find (2V 7x2 ). (2i/72)' = ' 3 2°(V7x2) Raise each factor of 27x? to the 3rd power. (Ox )(7x2) Evaluate: 23 = 8. Use (v5)" = = a. = 56x2 Multiply: 8 · 7 = 56 (6) (3 - V3)° - (8 - v3)(8 - v3) 2 – V3 V3 (c) Write the base 8 3 as a factor twice. %D 64 – 8V3 - 8/3 + V3 V 3 Use the FOIL method %3D = 64 – 16V3 + 3 Combine like radicals: -8/3 - 8/3 = -16/3. = 67 – 16/3 Combine like terms: 64 + 3 = 67. Success Tip 2 (8 - v3)* Since has the form (x – y)², we could also use a special product rule to find this square of a difference quickly. (d) We can use the FOIL method to find the product. (/m + 1 + 2)? = (Vm + 1 + 2)(/ m + 1 + 2 - (vm + 1)* + 2/ m + 1 + 2/m + 1 + 2· 2 = = m + 1 + 2/ m + 1 + 2Vm + 1 + X (va)" = Use = a. = m + 4V m + 1 + Combine like terms.
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