Example 4c) find lim x-0 lim x→0 √x+1-1 lim =1-1 √x+1-1 1-1 0 0 X-0 X 0 Multiply top & bottom by the conjugate: √x+1+1 lim x→0 X √√x+1-1 √√x+1+1 √x+1+1 x+1-1 1 = lim x (√x+1+1) 0 √√x+1+1 2

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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How does it equal 1/2? When I keep getting 0/0 even after multiplying the numerator and the denominator by the conjugate.
s if it indeed exists, (and they are covered in chapter 24 of
determinate (we cannot determine whether or not the limit
e* - 1
x+0x²²x
nd lim-
-1
0
-1 O
ing can be done,
inate. Later, you
e-1
2
0x²-x
=-1.
Example 4c) find lim
X-0
lim
X-0
lim
X-0
√√x+1-1 1-1 0
1110
=
lim
X-0
Multiply top & bottom by
the conjugate: √√x+1+1
√x+1-1
x+1-1
x (√x + 1 + 1)
√√x+1-1 √x+1+1
X
√x+1+1
=
X
1
0 √√x+1+1 2
lim
Transcribed Image Text:s if it indeed exists, (and they are covered in chapter 24 of determinate (we cannot determine whether or not the limit e* - 1 x+0x²²x nd lim- -1 0 -1 O ing can be done, inate. Later, you e-1 2 0x²-x =-1. Example 4c) find lim X-0 lim X-0 lim X-0 √√x+1-1 1-1 0 1110 = lim X-0 Multiply top & bottom by the conjugate: √√x+1+1 √x+1-1 x+1-1 x (√x + 1 + 1) √√x+1-1 √x+1+1 X √x+1+1 = X 1 0 √√x+1+1 2 lim
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