EXAMPLE 4.9Draw the shear and moment diagrams for the beam shown in Fig. 4-13.The support reactions have been calculated.4-13.9 kNStarts atslopeof +9-3 mV (KN)96 kN/mM (kN-m)-3 m-w negative increasingV slope negative increasing9 KN3V negative increasingM slope negative increasing18-x (m)6Ends at-slopeof -9x (m)

Given Load 6 kN/m UVLSpan 6mTo find out SFDBMD

EXAMPLE 4.9 Draw the shear and moment diagrams for the beam shown in Fig. 4-13. The support reactions have been calculated. 4-13. 9 kN Starts at slope of +9 -3 m 6 kN/m M (kN-m) -3 m- w negative increasing V (kN) V slope negative increasing 9 9 kN 3 V negative increasing M slope negative increasing 18 -x (m) 6 Ends at -slope of -9 x (m)

EXAMPLE 4.9 Draw the shear and moment diagrams for the beam shown in Fig. 4-13. The support reactions have been calculated. 4-13. 9 kN Starts at slope of +9 -3 m 6 kN/m M (kN-m) -3 m- w negative increasing V (kN) V slope negative increasing 9 9 kN 3 V negative increasing M slope negative increasing 18 -x (m) 6 Ends at -slope of -9 x (m)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Graphical Methods

The graphical method is a method of solving equations involving more than one variable using the Cartesian coordinate system. In civil engineering, the use of the graphical method is limited to the problems involving two variables. The graphical method has a great impact in solving the questions regarding engineering mechanics.

Question

EXAMPLE 4.9
Draw the shear and moment diagrams for the beam shown in Fig. 4-13.
The support reactions have been calculated.
4-13.
9 kN
Starts at
slope
of +9
-3 m
V (KN)
9
6 kN/m
M (kN-m)
-3 m-
w negative increasing
V slope negative increasing
9 KN
3
V negative increasing
M slope negative increasing
18
-x (m)
6
Ends at
-slope
of -9
x (m)

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