Example 4.4. A base line was measured in catenary as shown below, with a tape of nominal length 30 m. The tape measured 30.015 m when standardized in catenary at 20°C and 5 kgf tension. If the mean reduced level of the base was 30.50 m OD, calculate its true length at mean sea level. Given: weight per unit length of tape = 0.03 kg/m (w); density of steel = 7690 kg/m³(p); coefficient of expansion = 11 x 10–6 per °C; E = 210 x 10³ N/mm²; gravitational acceleration g = 9.806 65 m/s²; radius of the Earth = 6.4 x 10° m (R). (KU) Bay Measured length Temperature Applied tension Difference in level (m) (°C) (kgf) (m) 30.050 21.6 0.750
Example 4.4. A base line was measured in catenary as shown below, with a tape of nominal length 30 m. The tape measured 30.015 m when standardized in catenary at 20°C and 5 kgf tension. If the mean reduced level of the base was 30.50 m OD, calculate its true length at mean sea level. Given: weight per unit length of tape = 0.03 kg/m (w); density of steel = 7690 kg/m³(p); coefficient of expansion = 11 x 10–6 per °C; E = 210 x 10³ N/mm²; gravitational acceleration g = 9.806 65 m/s²; radius of the Earth = 6.4 x 10° m (R). (KU) Bay Measured length Temperature Applied tension Difference in level (m) (°C) (kgf) (m) 30.050 21.6 0.750
Chapter2: Loads On Structures
Section: Chapter Questions
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Transcribed Image Text:Example 4.4. A base line was measured in catenary as shown below, with a tape of nominal length 30 m.
The tape measured 30.015 m when standardized in catenary at 20°C and 5 kgf tension. If the mean reduced
level of the base was 30.50 m OD, calculate its true length at mean sea level.
Given: weight per unit length of tape = 0.03 kg/m (w); density of steel = 7690kg/m³(p); coefficient
of expansion = 11 × 10-6 per °C; E = 210 x 10° N/mm²; gravitational acceleration g = 9.806 65 m/s²;
radius of the Earth = 6.4 × 106 m (R).
(KU)
Bay Measured length Temperature Applied tension Difference in level
(m)
(°C)
(kgf)
(m)
1
30.050
21.6
5
0.750
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