Example 4.2: Use the the circuit 201 4.2: Use the node-voltage power dissipated рошет + shown in Fig. 4.10. 2 Node voltage at V₁ - 20 2 Node Voltage V₂ - V₁ 5 + + node + 1 V₁ 20 V₁ + 20 at method to find in the 5-2 resister in the V₁ + V₂ 10 Problem: We have Solution: Express is, the the voltages! 51 www - V₁ - V/₂ 5 + V₂ 10₂ V₂ 12-810 2 2 = 24 www - O two equations, but con bralling 10 = V₁ V₂ but three un/knowns. in terms of Big curmat using passive sign convention
Example 4.2: Use the the circuit 201 4.2: Use the node-voltage power dissipated рошет + shown in Fig. 4.10. 2 Node voltage at V₁ - 20 2 Node Voltage V₂ - V₁ 5 + + node + 1 V₁ 20 V₁ + 20 at method to find in the 5-2 resister in the V₁ + V₂ 10 Problem: We have Solution: Express is, the the voltages! 51 www - V₁ - V/₂ 5 + V₂ 10₂ V₂ 12-810 2 2 = 24 www - O two equations, but con bralling 10 = V₁ V₂ but three un/knowns. in terms of Big curmat using passive sign convention
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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I need help solving for i-phi
Transcribed Image Text:ZVk₂
хо
201
+ √₂ + 5 V/2
TO TO Tie
10
-201-8V₁
10
- IOU,
10
10
2 V2
10
-
+ Vz
10
84₁
To
+5Vz
8 V₂
10
-8V2
10
Transcribed Image Text:Example 4.2: Use the
the
circuit
201
power dissipated
2
shown in Fig. 4.10.
گرام
21
www
Node voltage at Vi
V₁ - 20
V₁
Node Voltage
√₂-V₁
5
V₁
5
十
+
+
+
V₂
10
20
V₂
10
1/2
10
1
20
+
+
+
at
+
Problem: We have
Solution: Express is the controlling
the
поле
voltages!
node - Voltage
in the 5-1
52
www
V₂
+
N
V₂ ≥ 10
V₁ - V/₂
5
Substitute this relationship in to equation 2
V₂ - V₁
V₂
8
1/(
5
2
1/₂
12₂-810
2
2
two equations, but
24
www
= 0
8v,
10
method
resister in the
систnt
using passive sign convention
10 = V₁-1₂
5
V₁ – U₂
5
8V₂
10
to find
three unlenowns.
in terms of
Big
=0
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