EXAMPLE 4 Evaluate the following integrals by interpreting each in terms of areas. (a) dx (b) 2) dx SOLUTION (a) Since f(x) = V9 - x->0, we can interpret this integral as the area under the curve y= V9- x² from 0 to But since y= we get x + y = 9, which shows th the graph of fis a quarter-circle with radius in the top figure. Therefore, -x² dx = r(3)² = %3D

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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EXAMPLE 4
Evaluate the following integrals by interpreting each in terms of areas.
(a)
xp
(b)
(x-2) dx
SOLUTION
(a) Since f(x) = V9 - x'2 0, we can interpret this integral as the area under the curve
y= V9-xe from 0 to
But since y-
we get
x2
+ y= 9, which shows tha
the graph of fis a quarter-circle with radius
lin the top figure. Therefore,
9- x2 dx =
Transcribed Image Text:EXAMPLE 4 Evaluate the following integrals by interpreting each in terms of areas. (a) xp (b) (x-2) dx SOLUTION (a) Since f(x) = V9 - x'2 0, we can interpret this integral as the area under the curve y= V9-xe from 0 to But since y- we get x2 + y= 9, which shows tha the graph of fis a quarter-circle with radius lin the top figure. Therefore, 9- x2 dx =
(b) The graph of y = x- 2 is the line with slope
shown in the bottom figure. We compute the
integral as the difference of the areas of the two triangles:
2%3D
(x-2) dx = A, - A2 -
Transcribed Image Text:(b) The graph of y = x- 2 is the line with slope shown in the bottom figure. We compute the integral as the difference of the areas of the two triangles: 2%3D (x-2) dx = A, - A2 -
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