In Example 3.6.2, why is it that x = 3 is not an inflection point, even though the concavity of the graph changes from concave down to concave up at x = 3? Example 3.6.2Sketch the graph ofy = f(x)(2)Answer: A. The function is not defined at 3, so the domain of ƒ is (-∞, 3) U (3, ∞).B. For the y-intercept, set x=: 0, so f(0) = 0 and the y-intercept is (0,0).For the x-intercept set y = 0 in (2)It follows that x-=XXXX30, so the x-intercept is also the origin.C. In the rational function given by (2), we have both odd powers of x (x¹ is odd) andeven powers of x (−3 = −3xº is even), so f is neither even nor odd.

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Answered: Example 3.6.2 Sketch the graph of y =…

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter3: Functions

Section3.3: More On Functions; Piecewise-defined Functions

Problem 5SC

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In Example 3.6.2, why is it that x = 3 is not an inflection point, even though the concavity of the graph changes from concave down to concave up at x = 3?

Example 3.6.2
Sketch the graph of
y = f(x)
(2)
Answer: A. The function is not defined at 3, so the domain of ƒ is (-∞, 3) U (3, ∞).
B. For the y-intercept, set x
=
: 0, so f(0) = 0 and the y-intercept is (0,0).
For the x-intercept set y = 0 in (2)
It follows that x
-
=
X
X
X
X
3
0, so the x-intercept is also the origin.
C. In the rational function given by (2), we have both odd powers of x (x¹ is odd) and
even powers of x (−3 = −3xº is even), so f is neither even nor odd.

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I wanted you to answer this question: In Example 3.6.2, why is it that x = 3 is not an inflection point, even though the concavity of the graph changes from concave down to concave up at x = 3? based on the question. I did not want to you do the graph. Thanks

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