Example 3. The wall exerts a 600 N force on an 80-kg person moving at 4 m/s on a circular platform. What is the radius of the circular path? Draw and label sketch Newton's 2nd law m = 80 kg; V = 4 m/s F = 600 N for circular motion: mv F = F r = ? (80 kg)(4 m/s)² r = 2.13 m 600 N
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- Roads are often banked (see above) to make travelling around comers safer. In the case of a banked road where does the centripetal force come from? Select one: O a. The weight of the car Ob. The reaction force O Friction Answer: A highway corner of radius 350 m is banked at 15. A car of mass 1400 kg travels round this comerg=9.8m/s/s What is the value of the weight force? Answer State the size of the vertical component of the reaction force (F)? Answer F What is the size of the reaction force F? 15° Answer What is the size of the horizontal component of F? Answer Calculate the speed of the car Answer Calculate the time taken to travel around the corner. Assume the comer is one sixteenth of a circle.After eating all your candy, you ride the Silly Silo, which sounds like an awful idea. The Silly Silo is a ride that used to be at Adventure Land. Watch the video at this link to see how it works. Notice that the floor drops out and everyone stays stuck to the wall. Imagine that the Silly Silo has a diameter of 5.5 m and it spins with a tangential velocity of 6.1 m/s. - What is the centripetal acceleration of a person stuck against the wall? - What is the minimum coefficient of friction that allows everyone to stick to the wall (and not slide up or down) during the ride.The centripetal force of an object of mass is given by F(r)=mv^2 / r, where v is the speed of rotation and r is the distance from the center of rotation. Need help in explaing what concepts are being used and why it is important. Thank you Answer the following: Draw a graph or figure to represent this situation. Describe how the concepts from this module can be applied in this case. Find the rate of change of centripetal force with respect to the distance from the center of rotation. Provide another example of a scenario that involves the same concept.
- Need help solving the number of force in plane, centripetal force and if all forces are balanced.A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.15 m/s - Calculate the centripetal acceleration of the child. - Calculate the net horizontal force exerted on the child. (mass = 34.5 kg)Need help checking practice problems, image included. Thanks!
- Children of mass 54 kg ride on a Ferris wheel as shown in Figure. Children move in a vertical circle of radius 14.5 m at a constant speed of 2.85 m/sec. = 0.56 m/sec² a) What is the centripetal acceleration each of the children? Answer: ac b) What is the normal force from the chair when a child is at the Top of the circle, as shown in the Figure? Draw a Free-Body Diagram for this situation in the figure below. Answer: NTop = 499.0 N c) What is the normal force from the chair when a child is at the Bottom of the circle, as shown in the Figure? Draw a Free-Body Diagram for this situation in the figure below. Answer: N Bottom = 559.4 N Top 7 Bottom RA jet pilot takes his aircraft in a vertical loop , if the jet is moving at a speed of 1140 km/m , at the lowest point of the loop , determine the minimum radius (r) of the circle , so that the centripetal acceleration at the lowest point doesn't exceed 6.4 g's please pay attention , previously you sent the answer , but that was not correct , that's why i am sending againCentripetal Force: I'm trying to understand the forces at work in centripital force, i understand that if an object is moving in a circle then their must be a net inward acceleration. So if centripetal force is what is pushing in on the object toward the center of the circle, then what is pushing outward to counteract this force and hold the object in its rotation? Like a tenis ball on a string, if i swing it and it gain an inward force, then as it swings under that logic it would approach my hand. What is pushing it out?
- If centripetal force is directed toward the center of curvature, why do you feel as if you are “thrown” away from the center as a car goes around a curve? Explain.What is the maximum speed with which a 1300 kg car can round a turn of radius 100.0 m if the coefficient of static friction between the tires and the road is 0.70? Does the result depend onthe mass of the car? What is the centripetal acceleration of the car at the maximum speed it can go around the turn? What is the corresponding centripetal force on the car?A 1000 kg race car is traveling at 60 m/s around a curved section of track that has a radius of 300 m. a) what is the cars centripetal acceleration? b)