8 we?Example 3. Find the density of a metallic body which floats at the interface of mercury ofspecific gravity 13.6 and water such that 35 percent of its volume is submerged in mercury and 65percent in water. Yww.Solution. Let, V= Volume of the body, m'Then, volume of body submerged in mercuryMetallic body35Waterx V= 0.35 V m100Volume of body submerged in water65x V= 0.65 V m100MercuryThe body will be in equilibrium when,Total buoyant (upward) force = weight ofthe body%3D

Answered: Image /qna-images/answer/06597611-77f5-49aa-a784-790e49f350d1.jpg

Example 3. Find the density of a metallic body which floats at the interface of mercury of specific gravity 13.6 and water such that 35 percent of its volume is submerged in mercury and 65 percent in water www

Example 3. Find the density of a metallic body which floats at the interface of mercury of specific gravity 13.6 and water such that 35 percent of its volume is submerged in mercury and 65 percent in water www

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)

5th Edition

ISBN:9781305084766

Author:Saeed Moaveni

Publisher:Saeed Moaveni

Chapter6: Fundamental Dimensions And Units

Section: Chapter Questions

Problem 25P

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Question

100%

8 we?
Example 3. Find the density of a metallic body which floats at the interface of mercury of
specific gravity 13.6 and water such that 35 percent of its volume is submerged in mercury and 65
percent in water. Y
ww.
Solution. Let, V= Volume of the body, m'
Then, volume of body submerged in mercury
Metallic body
35
Water
x V= 0.35 V m
100
Volume of body submerged in water
65
x V= 0.65 V m
100
Mercury
The body will be in equilibrium when,
Total buoyant (upward) force = weight of
the body
%3D

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