Example 3: Given thatP(A) = 0.17, P (B) =0.22, P (A or B) = 0.33:(a) Compute P(A and B).(b) Are the two eventsmutually exclusive?Explain.(c) Are these two eventsindependent of eachother? Explain?

Answered: Example 3: Given that P(A) = 0.17, P(B)…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Identify why this assignment of probabilities cannot be legitimate: P(A) = 0.4, P(B) = 0.3, and P(A and B)=0.5 (A) A and B are not given as disjoint events (B) A and B are given as independent events (C) P(A and B) cannot be greater than either P(A) or P(B) (D) The assignment is legitimate
1and P(B) 0.76 0.855 0.595 0.55
K Find P(A or B or C) for the given probabilities. P(A)=0.39, P(B) = 0.22, P(C) = 0.11 P(A and B) = 0.12, P(A and C) = 0.02, P(B and C) = 0.07 P(A and B and C) = 0.01 P(A or B or C) =
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Foreign freshmen are required to take an English placement exam. Over the past several years, 20% of the new students have failed the test and have been placed in remedial classes. In a sample of n = 100 studentsfrom this year’s class, only 12 failed the test.
Let A and B be two events such that P (A) = 0.78 and P(B) = 0.01. %3D Do not round your responses. (If necessary, consult a list of formulas.) (a) Determine P (A U B), given that A and B are independent. (b) Determine P (A U B), given that A and B are mutually exclusive.
For each set of probabilities, determine whether the events A and B are independent or dependent. (If necessary, consult a list of formulas.) Probabilities Independent Dependent = P(A 18) - 1 (a) P(A)=-;P(B) =;P(A\B) = 5 1 1 P(A) =;P (B) = P(A and B) = %3D 4 6. 1 1 P (B|A) = 1 (c) P(4)-극: P(B)-P(Bl4): %3D %3D 1 1 (d) P(A) = : P(B) = P(4 |B) = | %3D
Event E and event F are independent. Fiven P(E) = 0.3, P = (F) 0.5, compute P(E and F) and P(E or F). a) P(E and F) = b ) P(E or F)
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The Addition Rule for the probability that events A or B or C will occur, P(A or B or C), is given by P(A or B or C)=P(A) + P(B) + P(C) - P(A and B)- P(A and C) - P(B and C) + P(A and B and C) Find P(A or B or C) for the given probabilities. P(A) = 0.32, P(B) = 0.24, P(C) = 0.11 P(A and B) = 0.13, P(A and C) = 0.03, P(B and C) = 0.08 P(A and B and C) = 0.01 P(A or B or C) = montesino P Pearson DELL S Hummert mana SEFERDESSERTS SIEMENS se fa m Next Copyright © 2022 Pearson Education Inc. All rights reserved. | Terms of Use | Privacy Policy | Permissions Contac

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Example 3: Given that P(A) = 0.17, P(B) = 0.22, P(A or B) = 0.33: (a) Compute P(A and B). (b) Are the two events mutually exclusive? Explain. (c) Are these two events independent of each other? Explain?