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Example 3 For the circuit shown in Figure 2, find the current (1) and voltages Vo V, and V2. Solution: The two sources are aiding each other in the closed loop; the diode is on and can be replaced by a closed switch. Applying Kirchhoff's voltage law (KVL) E1- V1- V2 + =E2 = 0 E,- I(R;) – I(R2) + E2 = 0 Solving for I, |= (E, + E2) / (R, + R2) = 25/7 = 3.5 mA V, = I x R, = 17.5 V V2 = I x R2 = 7.0 v Ry Sk R2 - 20 V 2k

Example 3 For the circuit shown in Figure 2, find the current (1) and voltages Vo V, and V2. Solution: The two sources are aiding each other in the closed loop; the diode is on and can be replaced by a closed switch. Applying Kirchhoff's voltage law (KVL) E1- V1- V2 + =E2 = 0 E,- I(R;) – I(R2) + E2 = 0 Solving for I, |= (E, + E2) / (R, + R2) = 25/7 = 3.5 mA V, = I x R, = 17.5 V V2 = I x R2 = 7.0 v Ry Sk R2 - 20 V 2k

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Example 3 For the circuit shown in Figure 2, find the current (1) and voltages Vo V, and V2. Solution: The two sources are aiding each other in the closed loop; the diode is on and can be replaced by a closed switch. Applying Kirchhoff's voltage law (KVL) E,-V1- V2 + =E2 = 0 E,- I(R;) – I(R2) + E2 = 0 Solving for I, | = (E, + E2) / (R, + R2) = 25/7 = 3.5 mA V, = I x R, = 17.5 V V2 = I x R2 = 7.0 v Ry Sk R2 - 20 V 2k SV Figure 2
Transcribed Image Text:Example 3 For the circuit shown in Figure 2, find the current (1) and voltages Vo V, and V2. Solution: The two sources are aiding each other in the closed loop; the diode is on and can be replaced by a closed switch. Applying Kirchhoff's voltage law (KVL) E,-V1- V2 + =E2 = 0 E,- I(R;) – I(R2) + E2 = 0 Solving for I, | = (E, + E2) / (R, + R2) = 25/7 = 3.5 mA V, = I x R, = 17.5 V V2 = I x R2 = 7.0 v Ry Sk R2 - 20 V 2k SV Figure 2
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